Q1. Sum of cost price of two watches is Rs 3360. One watch is sold at a profit of 12% and other at a loss of 12%. Due to this transaction, there is neither profit nor loss. Find the cost price of each watch.
(a) Rs 1680, Rs 1680
(b) Rs 1280, Rs 1280
(c) Rs 1000, Rs 1000
(d) Rs 2100, Rs 2160
Q2. A seller buys 50 kg oranges for Rs 525 and gains a profit equal to the cost price of 10 kg of oranges. Find the selling price per kg of oranges (Rs/kg).
(a) 12.60
(b) 11.60
(c) 10.20
(d) 12
Q3. Find a number, one-seventh of which exceeds its eleventh part by 100.
(a) 1925
(b) 1825
(c) 1540
(d) 1340
Q4. 6 bells commence tolling together and toll of intervals are 2, 4, 6, 8, 10 and 12 s, respectively. In one hour, how many times do they toll together?
(a) 16
(b) 32
(c) 21
(d) 31
Q5. A certain type of board is sold in lengths of multiples of 2 ft. the shortest board sold is 6 ft and the longest is 24 ft. A builder needs a large quantity of these types of board in 5 1/2 ft lengths. Find the length of be ordered for which waste is minimum.
(a) 24 ft
(b) 26 ft
(c) 22 ft
(d) 52 ft
Q6. On mixing two classes A and B of students having average marks 25 and 40 respectively. The over all average obtained is 30. Find the ratio of the students in the class A and B.
(a) 2 : 1
(b) 5 : 8
(c) 5 : 6
(d) 3 : 4
Q7. At present the ratio of the age of Maya and Chhaya is 6 : 5 and fifteen years from now, the ratio will get changed to 9 : 8. Maya’s present age is
(a) 21 years
(b) 24 years
(c) 30 years
(d) 40 years
Q8. What must be added to each term of the ratio 7 : 11, so as to make it equal to 3 : 4?
(a) 8
(b) 7.5
(c) 6.5
(d) 5
Q9. The sum of three numbers is 68. If the ratio of the first to the second be 2 : 3 and that of the second to the third be 5 : 3, then the second number is
(a) 30
(b) 58
(c) 20
(d) 48
Q10. Two number are in the ratio 4 : 5 and their L.C.M. is 180. The smaller number is
(a) 9
(b) 15
(c) 36
(d) 45
Solutions:
S1. Ans.(a)
Sol.
On one watch, he earns 12% profit and on the other one 12% loss. There is, finally, no profit no loss.
Hence CPs of both the watches should be same such that their summation = Rs 3360.
Hence CP/watch = (Rs.3360)/2 = Rs. 1680
Hence option (a) is the answer.
S2. Ans.(a)
Sol.
Assume SP/kg = Rs x/kg.
CP/kg =(Rs.525)/50 = Rs. 10.5/kg
Total SP – Total CP = profit ⇒ 50x – Rs. 525 = 10 × Rs. 10.5 = Rs. 105
Or, 50x = Rs. 105 + Rs. 525 = Rs. 630
Hence x =(Rs.630)/50 = Rs. 12.6/kg
S3. Ans.(a)
Sol.
Let the number be x.
x/7- x/11 = 100
(11x-7x)/(11 x 7)=100
4x = 77 x 100
x = 1925
S4. Ans.(d)
Sol.
LCM of 2, 4, 6, 8, 10, 12 = (2 × 2 × 3 × 2 × 5) = 120
∴ After every 2 min they toll together
∴ Number of times they toll together in one hour
=(60/2+1) times = 31 times
S5. Ans.(c)
Sol.
LCM of (2 and 5 1/2) = LCM of (2 and 11/2)
Required answer = (LCM of 2 and 11)/(HCF of 1 and 2)=22/1 = 22 ft
S8. Ans.(d)
Sol.A/B=7/11 Given
Let x be added to both A & B
⇒(7+x)/(11+x)=3/4
Cross multiply the equation
28 + 4x = 33 + 3x
x = 5
S9. Ans.(a)
Sol. A + B + C = 68
A : B : C
2 : 3
5 : 3
▁(¯(10∶15∶9))
10x + 15x + 9x = 34x
34x = 68
x = 2
∴ A = 2 × 10 = 20
B = 2 × 15 = 30
C = 9 × 2 = 18
S10. Ans.(c)
Sol.
A : B
4 : 5
4x : 5x
LCM = 4 × 5 × x = 20x
20x = 180
x = 9
∴ Smallest number is
= 4 × 9 = 36
Largest number is = 5 × 9 = 45
