Q1. A man borrows Rs 6000 at 20% compound interest per annum. At the end of each year he pays back Rs 2000. How much amount he pay at the end of 3rd year to clear all his dues?
(a) Rs 5,088
(b) Rs 5,530
(c) Rs 5,453
(d) Rs 3,088
Q2. The ratio of two numbers is 1 2/3:2 1/4. If each of the number is increased by 10 the ratio becomes 4:4 1/2. the bigger number is
(a) 8.5
(b) 7.5
(c) 9
(d) 12.5
Q3. One type of liquid contains 30% of milk, the other contains 45% of milk. A container is filled with 3 parts of the first liquid and 7 parts of the second liquid. The percentage of milk in the mixture is:
(a) 40.5%
(b) 41%
(c) 39%
(d) 38.5%
Q4. A, B, and C have amounts in the ratio of 4 : 5 : 6. First B gives 1/5 th to A and 1/5 th to C then C gives 1/7 th to A. Find the final ratio of amount of A, B and C, respectively:
(a) 3 : 2 : 3
(b) 1 : 2 : 2
(c) 2 : 2 : 1
(d) 2 : 1 : 2
Q5. A shopkeeper gave an additional 15 per cent concession on the reduced price after giving 20 per cent standard concession on an article. If Arpit bought that article for Rs. 1,360, what was the original price?
(a) Rs. 3000
(b) Rs. 2400
(c) Rs. 2500
(d) Rs. 2000
Q6.In an election 20% of the voters did not cast their votes and 60 votes were declared invalid. The winner got 52% of valid votes and won by 116 votes. Find the total number of voters assume that only contestant were in the election.
(a) 4700
(b) 3800
(c) 4000
(d) 3700
Q7.If sum of upstream and downstream speed of a boat is 82 kmph, and the boat travels 105 km. upstream in 3 hr,Find the time taken by boat to cover 126 km downstream.
(a) 126/47 hr
(b) 127/47 hr
(c) 129/47 hr
(d) can’t be determined
Q8.A shopkeeper allows 5% discount and also allows 2 article free on purchase of 14 article. In this way he earns 40% profit. Find by what percent above the CP he marked the goods.
(a) 68.42%
(b) 70%
(c) 72%
(d) 74%
Q9.15 litre of a mixture contains alcohol and water in the ratio 1 : 4. If 3 litre of water is mixed in the mixture. The percentage of alcohol in the new mixture is
(a) 150/6%
(b) 100/3%
(c) 25%
(d) 50/3%
Q10.Find the area of the trapezium, whose parallel sides are 10 cm and 12 cm, and distance between the parallel sides is 11 cm.
(a) 121 cm²
(b) 122 cm²
(c) 123 cm²
(d) 124 cm²
Solutions:
S1. Ans.(a)
Sol.
Amount to be paid after the end of first year
=6000×120/100–2000
= 5,200
Amount to be paid after the end of second year
=5200×120/100–2000
= 4240
Amount to be paid after the end of third year
=4240×120/100
= 5088
S2. Ans.(b)
Sol.
Let the number are 5x/3 and 9x/4 respectively.
∴(5x/3+10)/(9x/4+10)=4/(9/2)
⇒4(5x+30)/3(9x+40) =8/9
⇒ 15x + 90 = 18x + 80
⇒x=10/3
∴Bigger no.=9/4×10/3
=7.5
S3. Ans.(a)
Sol.
Required percentage
=(30/100×3+45/100×7)/10×100
= 40.5%
S4. Ans.(d)
Sol.
Let A, B and C have amount 4x, 5x and 6x respectively.
A’s total amount → 4x + x + x
= 6x
B’s total amount → 5x – x – x
= 3x
C’s total amount → 6x + x – x
= 6x
∴ Required ratio = 6 : 3 : 6
= 2 : 1 : 2
S5. Ans.(d)
Sol.
Original price=1360×100/80×100/85
=2,000
S6. Ans.(d)
Sol.
Let the total voter be x
Total votes casted = 80/100 x = 0.8x
Valid votes = 0.8x – 60
Winner got = 52% valid votes
And won by 116 votes
(52% – 48%) = 116
52% – 48% = 116
4% = 116
100% = 2900
Also 0.8x – 60 = 2900
x = 3700
S7. Ans.(a)
Sol.
U = upstream speed ⇒ (b – w)
D = downstream speed ⇒ (b + w)
b = speed of boat in still water
w = speed of stream
∴ u + d = 82
b – w + b + w = 82
b = 41
ATQ,
41 –w=105/3=35
w = 6 kmph
b+w=126/t
t=126/47 hr.
S8. Ans.(a)
Sol.
1st discount = 5%
2nd discount=(2/16)×100
=12.5%
∴MP×95/100×87.5/100=140/100 CP
MP×19/20×7/8=7/5 CP
∴MP/CP=32/19
Required answer
=((32 –19)/19)×100
≃ 68.42%
S10. Ans.(a)
Sol.
Area of trapezium
=1/2×sum of parallel sides×height (distance between parallel sides)
=1/2 (10+12)×11
= 121 cm²
