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# Maths Questions for DSSSB Exam :5 July 2018 (Solutions)

Directions (1-5): The following line graph shows the total no. of Tigers and elephants in India in six different years.
Study the graph carefully and answer the following questions.

Q2.What is the average no. of total elephants over all the years?
(a) 825
(b) 950
(c) 850
(d) 770
Q3.What is the difference between total no. of elephants and total no. of Tigers over all the years?
(a) 850
(b) 800
(c) 750
(d) 725
Q4.The no. of Tigers in year 2011 and 2012 together is approximate what percent more or less than the no. of elephants in the same years together?
(a) 4% more
(b) 12% less
(c) 10% less
(d) 8% less
Q5.In the year 2017, if 10% Tigers are increased than previous year by application of ‘Save the Tigers’ by Indian government then what will be the ratio of Tigers in year 2017 to that of the Tigers in year 2012?
(a) 99 : 170
(b) 170 : 99
(c) 133 : 140
(d) 211 : 95
Directions (6-10): Study the following table carefully to answer the following questions.
Q6.Find the average of area of circle and cube(in sq.cm.).
(a) 377
(b) 424
(c) 426
(d) 428
Q7.Find the volume of the cylinder. If it’s volume is 100/3% more than the given cylinder.
(a) 5488 π cm³
(b) 5498 π cm³
(c) 5496 π cm³
(d) 5486 π cm³
Q8.Find the ratio of volume of cuboid to the volume of cube.
(a) 42 : 25
(b) 25 : 42
(c) 21 : 43
(d) 43 : 21
Q9.Find the total surface area of cylinder.
(a) 980 π cm²
(b) 1080 π cm²
(c) 935 π cm²
(d) 940 π cm²
Q10.Find the volume of the cone of same dimension as of the cylinder.
(a) 4312 cm³
(b) 4212 cm³
(c) 4412 cm³
(d) 4512 cm³

Solutions:

Solutions:

S2. Ans.(a)
Sol.
Required average
=1/6×(1000+950+850+800+650+700)
= 825

S3. Ans.(b)
Sol.
Required difference
=(1000+950+850+800+650+700)-(900+850+700+700+550+450)
= 4950 – 4150
= 800

S5. Ans.(a)
Sol.
Tigers in 2017
=450×110/100
= 495
∴ Required ratio
= 495 : 850
= 99 : 170

S6. Ans.(a)
Sol.
Area of circle = A=πr²
= 22/7×7×7
= 154 sq. cm
SA of cube = 6a²
= 6 × 10²
= 600
Avg=(600+154)/2=754/2
=377 sq.cm

S7. Ans.(a)
Sol.
Volume of cylinder (V₁)
= πr²h
= π (14)²(21)
= 4116π cm³
Volume of new cylinder
=4/3 V₁
=4/3×4116 π
= 5488 π cm³

S8. Ans.(a)
Sol.
Volume of cuboid = ℓ × b × h
= 10 × 12 × 14 cm³
= 1680 cm³

Volume of cube = a³
= 10 × 10 × 10
= 1000
Required ratio=1680/1000
=42/25
=42∶25

S9. Ans.(a)
Sol.
Total surface area of the cylinder
= 2πrh + 2πr²
= 2πr (h + r)
= 2π (14) (21 + 14)
= 28 π (35)
= 980 π cm²

S10. Ans.(a)
Sol.Volume of cone=1/3 πr² h
=1/3×22/7×(14)²×21
= 4312 cm³ Join India's largest learning destination

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