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# Maths Questions for DSSSB Exam 2017

Q1. Successive discounts of 10% and 30% are equivalent to a single discount of:
(a) 40%
(b) 35%
(c) 38%
(d) 37%

Q2. A trademan marks his good at 20% above the cost price. He allows his customers a discount of 8% on marked price. Find out his profit percent.
(a) 12%
(b) 10.4%
(c) 16%
(d) 20%

Q3. A discount of 2 1/2% is given to the customer on the marked price of an article. A man bought the article for Rs. 39. The marked price of the article is:
(a) Rs. 42
(b) Rs. 36.5
(c) Rs. 40
(d) Rs. 41.5

Q4. The marked price of a watch is Rs. 1000. A retailer buys it at Rs. 810 after getting two successive discounts of 10% and another rate which is eligible. What is the second discount rate?
(a) 15%
(b) 10%
(c) 8%
(d) 6.5%

Q5. A trader marked the price of his commodity so as to include a profit of 25%. He allowed discount of 16% on the marked price. His actual profit was:
(a) 5%
(b) 9%
(c) 16%
(d) 25%

Q6. A shopkeeper marks his sarees at 20% above the cost price and allows the purchaser a discount of 10% for cash buying. What profit percent does he marked?
(a) 18%
(b) 12%
(c) 10%
(d) 8%

Q7. A skilled, a half skilled and an unskilled labourer work for 7, 8 and 10 days respectively and they together get Rs. 369 for their work. If the ration of their each day’s work is 1/3 : 1/4 : 1/6, then how much does the trained labourer get (in rupees)?
(a) 164
(b) 102.50
(c) 201.50
(d) 143.50

Q8. A and B together can complete a piece of work in 12 days. A alone can complete in 20 days. If B does the work only half a day daily, then in how many days A and B together will complete the work?
(a) 10 days
(b) 20 days
(c) 11 days
(d) 15 days

Q9. If x can finish a job in 4 hours and y can finish the same job in 8 hours independently, then they together will finish the job in
(a) 140 minutes
(b) 120 minutes
(c) 160 minutes
(d) 150 minutes

Q10. Jaya completes 2/3 of his work in 10 days. Time he will take to complete 3/5 of the same work in
(a) 4 days
(b) 8 days
(c) 6 days
(d) 9 days
Solutions:
S1. Ans.(d)
Sol. x+y-xy/100
10+30-(30 × 10)/100
40 – 3
= 37%
S2. Ans.(b)
Sol. Increase% =((P + D) × 100)/(100-D)
20=((P+8) × 100)/92
92 = 5P + 40
52 = 5P
P = 10.4%
S3. Ans.(c)
Sol. 39=x×97.5/100
975x = 39000
x=39000/975
x = 40
S4. Ans.(b)
Sol. 810=1000×90/100×(100-D)/100
90 = 100 – D
D = 10%
S5. Ans.(a)
Sol. 25=(P+16)×100)/84
21 = P + 16
P = 5%
S6. Ans.(d)
Sol. 20=(P+10)×100)/90
90 = 5P + 50
5P = 40
P = 8%
S7. Ans.(d)
Sol. Skilled : Half Skilled : Unskilled
4 : 3 : 2
28 : 24 : 20
7 : 6 : 5
Skilled = 369 × 7/18
= 143.5
S10. Ans.(d)
Sol. Jaya = 10 × 3/2
= 15 unit
= 15 × 3/5
= 9 days