Dear Students!!! There is most general as well as a scoring section in all the competitive entrance examinations in the teaching field i.e “Mathematics”.Because in this section only one thing is work i.e your accuracy and that could be nourished with the daily practice. So, for this, we are providing you the daily quiz for all teaching exams i.e CTET Exam 2018, DSSSB Exam & STET Exam.
Q1. A bike coveres a distance of 240 km in 5 h. Again, it covers another distance of 260 km in 5 h. Find the average speed of the bike.
(a) 50 km/hr
(b) 40 km/hr
(c) 100 km/hr
(d) None of these
Q2. The average of five numbers is 496. If two of them are 117 and 140, find the average of remaining three numbers.
(a) 239
(b) 717
(c) 741
(d) 637
Q3. Income of x is greater than income of y by 25%. Income of y is how many percent lesser than that of x?
(a) 25%
(b) 30%
(c) 20%
(d) 22%
Q4. The difference between 78% of a number and 59% of the same number is 323. What is 62% of that number?
(a) 1054
(b) 1178
(c) 1037
(d) 1159
Q5. Find the value of x% of y + y% of x.
(a) 3% of xy
(b) 2% of xy
(c) 5% of xy
(d) 4% of xy
Note: Q6-10 are based on the given data in the following table. Read it carefully and solve the quesions.
The ratio of failed boys to girls is reverse of that of passed.
Q6. If in school A, 100 girls are failed in the test. Find the total strength of A.
(a) 1100
(b) 1300
(c) 1200
(d) 1400
Q7. Find the ratio of no. of boys passed from A to that of B.
(a) 4: 5
(b) 5: 4
(c) 6: 5
(d) 5: 6
Q9. If the difference between the failed boys to girls is 25 in school D. Find the ratio of passed to failed students from D.
(a) 3: 1
(b) 4: 1
(c) 2: 1
(d) 1: 2
Q10. Find the average number of passed students from all schools together.
(a) 872.5
(b) 842.5
(c) 832.5
(d) 862.5
Solutions
S1. Ans.(a)
Sol. Average speed = (Total distance covered)/(Total time taken)
=(240+260) / (5+5)
=500/10
=50 km/hr
S2. Ans.(c)
Sol. Sum of five numbers = 496 × 5 = 2480
Sum of two given numbers = 117 + 140 = 257
Sum of remaining three numbers = 2480 – 257 = 2223
∴ Average of these three numbers
=2223/3=741
S6. Ans.(c)
Sol. Ratio of failed students is reversed to the passed students
Ratio of failed students = 2: 1
∴ failed girls = 1x
Now 1x = 100
∴ total failed student 3x = 3 × 100 = 300
∴ total students = 300 + 900 = 1200
S9. Ans.(c)
Sol. Passed students from D = 450
Ratio of failed boys to girls = 5: 4
Difference = 5x – 4x = x
x = 25 Given
total failed students = 9x
= 9 × 25 = 225
Required ratio
=450/225 = 18/9 = 2/1
S10. Ans.(d)
Sol. Avg. of passed students
=(900+600+1500+450)/4
= 862.5
