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Maths Questions for DSSSB Exam : 16 March 2018 (Solutions)

Maths Questions for DSSSB Exam : 16 March 2018 (Solutions)_30.1
Q1.Railway fares of 1st, 2nd and 3rd classes between two stations were in the ratio of 8 : 6 : 3. The fares of 1st and 2nd Classes were subsequently reduced by 1/6 and 1/12 respectively. If during a year, the ratio between the passengers of 1st, 2nd and 3rd classes was 9 : 12 : 26 and total amount collected by the sale of tickets was Rs 1088, then find the collection from the passengers of 1st class?
(a) Rs 260
(b) Rs 280
(c) Rs 300
(d) Rs 320
Q2.The cost of digging a pit was Rs 1,347. How much will it cost (approximately)if the wages of workmen per day has been increased by 1/8 of the former wages and length of the working day decreased by 1/21 of the former period?
(a) Rs 1443
(b) Rs 1234
(c) Rs 1439
(d) Rs 1000
Q3.Cheap and Best, a kirana shop, bought some apples at 4 per rupee and an equal number at 5 per rupee. He then sold the entire quantity at 9 for 2 rupees. What is his percentage profit or loss?
(a) 1.23% loss
(b) 6.66% profit
(c) 8.888% profit
(d) No profit no loss
Q4.Find the selling price of goods if two salesmen claim to make 25% profits each, one calculating it on cost price while another on the selling price, the difference in the profits earned being Rs 100 and selling price being the same in both the cases.
(a) Rs 2000
(b) Rs 1600
(c) Rs 2400
(d) Rs 2500
Q5.Find the compound interest on Rs 64,000 for 1 year at the rate of 12% annum compounded after each four month (approximately).
(a) Rs 8215
(b) Rs 8000
(c) Rs 8185
(d) Rs.7580
Q6.The population of a city is 2,00,000. If only birth occurs in first year with a rate 6% per annum and in next year only death occurs with a rate 3 % per annum, then calculate the population of the city after 2 years.
(a) 2,12,090
(b) 2,06,090
(c) 2,05,640
(d) 2,12,000
Q7.One year ago, the ratio between Mahesh’s and Suresh’s salaries was 3 : 5. The ratio of their individual salaries of last year and present year is 2 : 3 and 4 : 5 respectively. If their total salaries for the present year are Rs 43000, what is the present salary of Mahesh?
(a) Rs 19000
(b) Rs 18000
(c) Rs 16000
(d) Rs 15500
Q8.A sink contains exactly 12 litres of water. If water is drained from the sink until it holds exactly 6 litres of water less than the quantity drained away. How many litres of water were drained away?
(a) 2 litres
(b) 6 litres
(c) 3 litres
(d) 9 litres
Q9.5 litres of water is added to a certain quantity of pure milk costing Rs 3 per liters. If by selling the mixture at the same price as before, a profit of 20% is made, then what is the amount of pure milk in the mixture?
(a) 20 litres
(b) 30 litres
(c) 25 litres
(d) 35 litres
Q10.A speaks the truth 3 out of 4 times, and B 5 out of 6 times. What is the probability that they will contradict each other in stating the same fact?
(a) 2/3
(b) 1/3
(c) 5/6
(d) 1/6
Solutions:
S1. Ans.(d)
Sol.
Let fares are 8x, 6x and 3x respectively and passengers in 1st, 2nd and 3rd classes are 9y, 12y and 26y respectively.
New fares of 1st and 2nd classes
=8x×5/6 and 6x×11/12
=20x/3 and 11x/2
∴ Total collection
=20x/3×9y+11x/2×12y+3x×26y 
⇒ 60xy + 66xy + 78xy = 1088 
⇒xy=16/3
∴ Fare from 1st class passengers 
=16/3×60=Rs.320 
S2. Ans.(a)
Sol.
New cost 
=1347×9/8×20/21
≃1443 
S3. Ans.(a)
Sol.
Total C.P. of two apples
=1/4+1/5
=9/20 rupees 
Total selling price of two apples
=2×2/9
=4/9 rupees 
∴ New profit⁄loss=(9/20–4/9)/(9/20)×100 
≃1.23% (loss)
S4. Ans.(a)
Sol.
Let S.P=x
If profit calculated on C.P then C.P = 0.8x
If profit calculated on S.P then C.P = 0.75x
A.T.Q.
0.8x-0.75x = 100
∴x =100/5×100=Rs.2000
S5. Ans.(b)
Sol.
C.I.=64000(1+(12×1/3)/100)^3–64000
=64000×(26/25)^3–64000
=71,991.296 –64000
=7991.296
≃8000
S6. Ans.(c)
Sol.
Population of city after two years
=2,00,000×106/100×97/100
=2,05,640 
Maths Questions for DSSSB Exam : 16 March 2018 (Solutions)_40.1
S8. Ans.(d)
Sol.
Let , required water to be drained out be x ℓ 
∴ x + x – 6 =12
⇒ x = 9 ℓ
Maths Questions for DSSSB Exam : 16 March 2018 (Solutions)_50.1
S10. Ans.(b)
Sol.
P (A speak truth)=3/4
P (B speak truth)=5/6
Required probability 
=3/4×1/6+1/4×5/6
=8/24
=1/3