Dear Students!!! There is most general as well as a scoring section in all the competitive entrance examinations in the teaching field i.e “Mathematics”.Because in this section only one thing is work i.e your accuracy and that could be nourished with the daily practice. So, for this, we are providing you the daily quiz for all teaching exams i.e CTET Exam 2018, DSSSB Exam & STET Exam.
Q1. Find the sum of first 5 multiples of 4.
(a) 40
(b) 50
(c) 60
(d) 70
Q2. Find the sum of first 4 multiples of 9.
(a) 80
(b) 90
(c) 100
(d) 105
Q3. The number of factors of 540 is
(a) 20
(b) 22
(c) 23
(d) 24
Q4. The total number of prime factors which are contained in (30)⁶ is
(a) 15
(b) 16
(c) 17
(d) 18
Q5. The number of factors of 60 are
(a) 10
(b) 12
(c) 14
(d) 15
Q6. Sum of all factors of 248 is
(a) 320
(b) 480
(c) 560
(d) 400
Q7. Sum of the factors 48 will be
(a) 124
(b) 130
(c) 132
(d) 136
Q8. The LCM of 12, 15, 18 and 20 would be
(a) 175
(b) 160
(c) 180
(d) 220
Q9. The LCM of 24, 48, 96 and 60 would be
(a) 440
(b) 480
(c) 465
(d) 484
Q10. Find the LCM of 2 × 3 × 5 × 7 and 3 × 5 × 7 × 11
(a) 2 × 3 × 5 × 7 × 11
(b) 2 × 3² × 3² × 7² × 11
(c) 3 × 5 × 7
(d) None of the above
Solutions
S1. Ans.(c)
Sol. First 5 multiples of 4 are as follow
4 × 1 = 4, 4 × 2 = 8, 4 × 3 = 12, 4 × 4 = 16
And 4 × 5 = 20
∴ Sum of first 5 multiples of 4
= 4 + 8 + 12 + 16 + 20
= 60
S2. Ans.(b)
Sol. First 4 multiples of 9 are as follow
9 × 1 = 9, 9 × 2 = 18, 9 × 3 = 27
And 9 × 4 = 36
∴ Sum of first 4 multiples of
9 = 9 + 18 + 27 + 36
= 90
S10. Ans.(a)
Sol. Required LCM = 2 × 3 × 5 × 7 × 11
