Q1. If length of each side of a rhombus PQRS is 8 cm and ∠PQR = 120°, then what is the length (in cm) of QS?
Q2. In the given figure, ABC is a triangle. The bisectors of internal ∠B and external ∠C interest at D. If ∠BDC = 48°, then what is the value (in degrees) of ∠A?
Q3. If Suresh sells an article at a price of Rs. 9300, he gets a profit of Rs. 3100. At what price should he sell the article so that he gets a profit of 25%?
(a) Rs. 7250
(b) Rs. 7350
(c) Rs. 7650
(d) Rs. 7750
Q4. The simple interest accrued in 4 years on a principal of Rs. 20,000 is one-tenth the principal. What is the rate of simple interest p.c.p.a.?
Q5. The compound interest on Rs. 2800 for 18 months at 10 per cent annum is:
(a) Rs. 441.35
(b) Rs. 436.75
(c) Rs. 434. 00
(d) Rs. 420.00
Q6. Three men or eight boys can do a piece of work in 17 days. In how many days can 2 men and 6 boys complete the same piece of work?
(a) 20 days
(b) 10 days
(c) 15 days
(d) 12 days
Directions (7-10): The pie chart given below shows the number of shoes of 5 different brands in a multi brand store. There are total 1200 shoes.
Q7. How many shoes are there of Reebok brand?
Q8. What is the difference in number of shoes of Puma and Vans?
Q9. The difference between the number of shoes of Reebok and Nike is same as the difference between which of the following two brands?
(a) Puma and Adidas
(b) Reebok and Adidas
(c) Vans and Nike
(d) Nike and Adidas
Q10. Puma shoes are how much percent more than the Nike Shoes?
Sol. In ∆ABC
∠A + 2y + (180 – 2x) = 180
⇒ ∠A = 2(x -y)..(i)
In ∆BCD, 48° + y + x + (180 – 2x) = 180
⇒ x – y = 48°…(ii)
⇒ from eqn (i) and (ii) we get
∠A = 96
Sol. C.P. of article
To gain 25%
S.P. = (6200×125)/100
= Rs. 7750
Sol. No. of shoes of Reebok brand
= 23% × 1200 = 276
Sol. Difference = 8% × 1200
Sol. Difference is same as 5% in (c).
Sol. No. of Puma shoes = 21% × 1200
No. of Nike shoes = 216
∴ % more =(252-216)/216×100