Q1. Two cones have their heights in the ratio 1:3 and the radii of their bases in the ratio 3:1. Find the ratio of their volumes?
(a) 3:1
(b) 2:1
(c) 4:1
(d) 5:1
Q2. Ram, Karan and Rohan invested capital in the ratio of 2:3:4 for time period of 6:4:3. Find the ratio of profit distributed?
(a) 12:13:14
(b) 13:12:14
(c) 13:14:12
(d) None of these
Q3. A sum of money becomes triple itself in 16 years on simple interest. In how many years will it become 5 times at the same rate?
(a) 32
(b) 15
(c) 27
(d) 30
Q4. The compound interest on Rs.30,000 at 7% per annum is Rs.4347. The period (in years) is:
(a) 2
(b) 2½
(c) 3
(d) 4
Q5. Thirty-five per cent of 740 is 34 more than a number. What is two-fifth of the number ?
(a)45
(b)90
(c)180
(d) 120
Q6. If 2x + 3y = 87 and 3x – 3y = 48, what is the value of x?
(a)11
(b)29
(c)72
(d) None of these
Q7. The no of revolutions a wheel of diameter 40cm makes in travelling a distance of 176m is
(a) 240
(b) 140
(c) 40
(d) 340
Q8. The curved surface area of a cylindrical pillar is 264 square meter and its volume is 924 cubic meters. Find the ratio of its diameter to its height
(a) 3 : 7
(b) 7 : 3
(c) 6 : 7
(d) 7 : 6
Q9. If the number X 78 Y is divisible by 55 then value of X and Y are :
(a) 1,0
(b) 4,5
(c) 6,5
(d) Data inadequate
Q10. What should come in place of the question mark (?) in the number series: 4, 6, 12, 14, 28, 30, ( ? )
(a) 60
(b) 62
(c) 64
(d) 32
SOLUTIONS
S1. Ans.(a)
Sol.Ratio of volume=(1/3 πr_1^2 h_1)/(1/3 πr_2^2 h_2 )=9/1×1/3=3∶1
S2. Ans. (d)
Sol.
Ratio of profit be
2 x 6 : 3 x 4 : 4 x 3 = 12 : 12: 12 = 1 : 1 : 1
S4. Ans. (a)
Sol.
Amount = Rs. (30000 + 4347) = Rs. 34347.
Let the time be n years.
Then, 30000 (1 + 7/100)n = 34347
(107/100)n = 34347/30000 = 11449/10000 = (107/100)2
So, the period is 2 years.
S5. Ans. (b)
Sol.
Number = 740 × 35/100 – 34 = 225
2/5 of the number = 90
S6. Ans.(d)
Sol.
2x+3y=87
3x –3y=48
5x = 135
x = 27
S7. Ans.(b)
Sol.
No.of revolutions=(Distance travelled)/Circumference
=(176×100)/2πr
=(176×100×7)/(2×22×20)
=140
S8. Ans.(b)
Sol.
2πrh = 264
π²h = 924
(πr^2 h)/2πrh=924/264
r/2=924/264
r = 7
D = 14
2×22/7×7×h=264
h=6
D : h = 14 : 6 = 7 : 3
S9. Ans.(b)
Sol.
Number which is divisible by 55, should be by 5, 11 also
For divisibility of 5. y should by 5 or 0,
For y= 0,
Divisibility by 11 ⇒ x + 8 = 7 + y
x + 8 = 7+ 0
x = -1 (Not possible)
For y= 5,
divisibility of 11 ⇒ x + 8 = 7 + y
x + 8 = 7 + 5
⬄ x + 8 = 7 + 5
x=12-8 =4
x = 4, y = 5
S10. Ans.(a)
Sol.
