Maths Questions for CTET,KVS Exam : 13th october 2018

Dear Students!!! There is most general as well as a scoring section in all the competitive entrance examinations in the teaching field i.e “Mathematics”.Because in this section only one thing is work i.e your accuracy and that could be nourished with the daily practice. So, for this, we are providing you the daily quiz for all teaching exams i.e CTET Exam 2018, DSSSB ,KVS,STET Exam.

Q2. Which of the following numbers is not a prime number?
(a) 197
(b) 313
(c) 439
(d) 391

Q3. A carpenter can build a cupboard in 64 hours. After 16 hours he takes a break. What fraction of the cupboard is yet to be built?
(a) 0.6
(b) 0.75
(c) 0.2
(d) 0.8

Q4. The bus fare between two cities is increased in the ratio 29:31. What is the increase in the fare, if the original fare is Rs 725 ?
(a) Rs 50
(b) Rs 775
(c) Rs 155
(d) Rs 310

Q5. In ΔABC, the angle bisector of ∠A cuts BC at E. Find the length of AC if lengths of AB, BE and EC are 9.6 cm, 4 cm and 3 cm respectively? 
(a) 4.8 cm
(b) 9.8 cm
(c) 7.8 cm
(d) 7.2 cm

Q6. If the volume of a cylinder is 385 cubic cm3 and height is 10 cm, find its radius?
(a) 7 cm
(b) 10.5 cm
(c) 3.5 cm
(d) 1.75 cm

Q7. What is the value of sec 5π/4?
(a) 1/ √3
(b) – √2
(c) – √3
(d) – 1

Q8. When 0.363636…..is converted into a fraction, then the result is _____.
(a) 7/11
(b) 4/11
(c) 14/33
(d) 8/33

Q9. If 25% of an electricity bill is deducted, Rs 1788 is still to be paid. How much was the bill?
(a) Rs 1430
(b) Rs 2420
(c) Rs 1466
(d) Rs 2384

Q10. If 5x – 1 < 3x + 2 and 5x + 5 > 6 – 2x; then x can take which of the following values?
(a) 0
(b) 1
(c) -1
(d) 2

Solutions

S1. Ans.(b)
Sol.
Discount % =(600-450)/600×100
= 25%

S2. Ans.(d)
Sol.
391 = 1 × 17 × 23
∴ 391 is not a prime number

S3. Ans.(b)
Sol.
Let the total work be 64 unit, so the carpenter build 1 unit
of cupboard in 1 hour.
So, Work done in 16 hours = 16 units
Work remaining = 64 – 16 = 48 units
Remaining work fraction =48/64=3/4
= 0.75

S4. Ans.(a)
Sol
Increase in fare =725/29×(31-29)
= Rs 50

S6. Ans.(c)
Sol.
Volume = 385 cm³
22/7×r^2×10=385
r = 3.5 cm

S7. Ans.(b)
Sol.
sec 5π/4=sec⁡〖 (π+π/4)〗
= -sec⁡〖π/4〗
= -√2

S9. Ans.(d)
Sol.
Original bill = 1788/((100 – 25))×100 = Rs. 2384

S10. Ans.(b)
Sol.
From, 5x – 1 < 3x + 2 ⇒ x < 1.5
From, 5x + 5 > 6 – 2x ⇒ x > 0.142
From all given option, only x = 1 satisfies both conditions.