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# Maths Questions for CTET,KVS Exam : 10th December 2018 (Solutions) Dear Students!!! There is most general as well as a scoring section in all the competitive entrance examinations in the teaching field i.e “Mathematics”.Because in this section only one thing is work i.e your accuracy and that could be nourished with the daily practice. So, for this, we are providing you the daily quiz for all teaching exams i.e CTET Exam 2018, DSSSB ,KVS,STET Exam.
Q 2. Find the number of prime factor of 20790.
(a) 7
(b) 9
(c) 11
(d) 13
(a) -129
(b) -163
(c) 129
(d) 163
Q 4. If x + y + z = 6 and xy + zx + zy = 10, then find the value of x3 + y3 + z3 – 3xyz.
(a) 16
(b) 26
(c) 36
(d) 46
Q 5. In a triangle ABC, a line is drawn from C which bisects AB at point D. Find the ratio of area of the triangles DBC and ABC.
(a) 1:1
(b) 2:1
(c) 1:2
(d) 1:3
Q 6. The area of a right angled triangle ABC, right angled at B, is 46 sq units. A median is drawn from A to BC which intersects at D. Find the area (in sq. units) of triangle ABD.
(a) 12
(b) 23
(c) 46
(d) 88
Q 7. X and Y give an exam. Difference of their marks is 45 and the difference of their marks is 15% of the maximum marks. What is the maximum marks for the exam?
(a) 180
(b) 450
(c) 150
(d) 300
Q 8. If P : Q : R = 6 : 7 : 8 and R : S = 3 : 5, then what is P : S?
(a) 18 : 25
(b) 9 : 20
(c) 11 : 24
(d) 16 : 45
Q 9. In what ratio must a mixture of 11% sugar strength be mixed with that of 25% sugar strength so as to get a new mixture of 13% sugar strength?
(a) 5 : 1
(b) 6 : 1
(c) 7 : 2
(d) 10 : 3
Q10. What is the average of 90, 250, 240, 204, and 616?
(a) 280
(b) 210
(c) 230
(d) 255
Solutions
S 1. Ans. (d)
Sol.
We have,
S 2. Ans.(a)
Sol.
We have,
N = 20790
= 2.3³.5.7.11
Number of prime factors = 1 + 3 + 1 + 1 + 1 = 7
S 3. Ans.(c)
Sol.
S 4. Ans.(c)
Sol.
We have,
x + y +z = 6 & xy + yz + zx = 10
∴ x² + y² + z² = (x +y +z)² – 2 (xy + yz + zx)
= 36 – 2 × 10 = 16
Now,
x³ + y³ + z³ -3xyz = (x +y+ z) (x² + y² + z² – xy -yz – zx)
= (6) (16 -10)
= 6 × 6 = 36
S 5. Ans.(c)
Sol. CD acts as a median , therefore ,