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# Maths Questions for All Teaching Exam :17th April 2019 (Solutions)

Q3. Fiftieth term of the pattern ABCDABCDABCD ……. is :
(a) A
(b) B
(c) C
(d) D

Q4. If 11 × 11 = 121
111 × 111 = 12231
1111 × 1111 = 1234321
Then 111111 × 111111 will be
(a) 123454321
(b) 12345654321
(c) 132546321
(d) 111 × 111× 111

Q5. Study the pattern below :
7 × 9 = 63
7 × 99 = 693
7 × 999 = 6993
7 × 9,999 = 69993
Continuing this pattern, the product of 7 × 99999 will be :
(a) 6993
(b) 69993
(c) 699993
(d) 6999993
Q6. Study the pattern given below :
9 × 11 = 99
9 × 11 = 1089
999 × 11 = 10989
9999 × 11 = 109989
Continuing the above pattern, the product of 9999999 × 11, without calculating will be :
(a) 109899
(b) 1099899
(c) 10999989
(d) 109999989
Q7. Look at the pattern given below :
(8 – 1) ÷ 7 = 1
(86 – 2) ÷ 7 = 12
(864 – 3) ÷ 7 = 123
(8642 – 4) ÷ 7 = 1234
Continuing this pattern, (86420 – 5) ÷ 7 will be :
(a) 12346
(b) 12364
(c) 12345
(d) 12435

Solutions:
S1. Ans.(d)
S2. Ans.(b)
S3. Ans.(c)
S4. Ans.(b)
S5. Ans.(c)
S6. Ans.(d)
S7. Ans.(c)
S9. Ans.(c)
S10. Ans.(c)