Maths Questions for All Teaching Exam :13th February 2019(Solutions)_00.1
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Maths Questions for All Teaching Exam :13th February 2019(Solutions)

Maths Questions for All Teaching Exam :13th February 2019(Solutions)_40.1

Dear Students!!! There is most general as well as a scoring section in all the competitive entrance examinations in the teaching field i.e “Mathematics”.Because in this section only one thing is work i.e your accuracy and that could be nourished with the daily practice. So, for this, we are providing you the daily quiz for all teaching exams i.e CTET Exam 2019, DSSSB ,KVS,STET Exam.


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Q1. The perimeter of the triangular base of a right prism is 15 cm and radius of the incircle of the triangular base is 3 cm. If the volume of the prism be 270 cm³ then the height of the prism is 
(a) 6 cm 
(b) 7.5 cm 
(c) 10 cm 
(d) 12 cm 

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Q6. If the radius of a cylinder is decreased by 50% and the height is increased by 50% to form a new cylinder, the volume will be decreased by 
(a) 0% 
(b) 25% 
(c) 62.5% 
(d) 75% 
Q7. A hemispherical cup of radius 4 cm is filled to the brim with coffee. The coffee is then poured into a vertical cone of radius 8 cm and height 16 cm. The percentage of the volume of the cone that remains empty is : 
(a) 87.5 % 
(b) 80.5% 
(c) 81.6% 
(d) 88.2% 
Q8. A right circular cylinder and a cone have equal base radius and equal height. If their curved surface are in the ratio 8 : 5, then the radius of the base to the height are in the ratio: 
(a) 2 : 3 
(b) 4 : 3 
(c) 3 : 4 
(d) 3 : 2 
Q9. The ratio of weights of two spheres of different materials is 8 : 17 and the ratio of weights per 1cc(cubic centimeter) of materials of each is 289 : 64. The ratio of radii of the two spheres is 
(a) 8 : 17 
(b) 4 : 17 
(c) 17 : 4 
(d) 17 : 8 
Q10. A large solid sphere is melted and molded to form identical right circular cones with base radius and height same as the radius of the sphere. One of these cones is melted and molded to form a smaller solid sphere. Then the ratio of the surface area of the smaller to the surface area of the larger sphere is 

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Answers 

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