Important Simplification Questions for UPTET 2019 | 20th December 2019_00.1
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Important Simplification Questions for UPTET 2019 | 20th December 2019

Important Simplification Questions for UPTET 2019 | 20th December 2019_40.1

UPTET Exam Practice Mathematics Questions

Dear Students!!! There is most general as well as a scoring section in all the competitive entrance examinations in the teaching field i.e Mathematics“.Because in this section only one thing is work i.e your accuracy and that could be nourished with the daily practice. With a proper system, Study Notes, Quizzes, Vocabulary one can quiet his/her nerves and exceed expectations in the blink of an eye. So, for this, we are providing you the daily quiz for all teaching exams i.e TET Exam 2019DSSSBKVSSTET Exam.

Q1. (120÷40+6-9) ×32=?
(a) 0
(b) 1
(c) 2
(d) 3

Q2. [(4241+49-16) ÷25]-2=?
(a) 168.75
(b) 168.85
(c) 168.24
(d) 168.96

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(a) 1.75
(b) 1.76
(c) 1.74
(d) 2

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(a) 9.64
(b) 9
(c) 8.65
(d) 9.96

Important Simplification Questions for UPTET 2019 | 20th December 2019_70.1

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(a) -2
(b) -1
(c) 7
(d) 2

Important Simplification Questions for UPTET 2019 | 20th December 2019_90.1

(a) 42
(b) 63
(c) 115
(d) 120

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(a) 0.75
(b) 0.25
(c) 0.432
(d) 1

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(a) 0
(b) 4
(c) 3
(d) 1

Q10. The cost of 24 Books and 72 pens is ₹8940. What is the cost of 4 Books and 12 Pens?
24 पुस्तकें और 72 पेन की लागत ₹8940 है. 4 पुस्तकें और 12 पेन की लागत क्या होगी?
(a) 1450
(b) 1500
(c) 1590
(d) 1490

Solutions

S1. Ans.(a)
Sol. (120÷40+6-9) ×32
Solve by BODMAS
= (3+6-9) ×32
= (9-9) ×32
= 0×32
= 0

S2. Ans.(d)
Sol. [(4241+49-16) ÷25]-2
= [(4290-16) ÷25]-2
= (4274÷25)-2
= 170.96-2
= 168.96

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S10. Ans.(d)
Sol. cost of 24 Books and 72 Pens = 8940
Cost of 4 Books and 12 Pens
6(4 Books + 12 Pens) = 8940
4 Books + 12 Pens = 8940/6= 1490


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