Important Maths Questions for UPTET 2019 | 31st December 2019_00.1
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Important Maths Questions for UPTET 2019 | 31st December 2019

Important Maths Questions for UPTET 2019 | 31st December 2019_40.1

UPTET Exam Practice Mathematics Questions

Dear Students!!! There is most general as well as a scoring section in all the competitive entrance examinations in the teaching field i.e Mathematics“.Because in this section only one thing is work i.e your accuracy and that could be nourished with the daily practice. With a proper system, Study Notes, Quizzes, Vocabulary one can quiet his/her nerves and exceed expectations in the blink of an eye. So, for this, we are providing you the daily quiz for all teaching exams i.e TET Exam 2019DSSSBKVSSTET Exam.

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Q3. A man bought Books worth ₹ 8000 and sold one-fourth of them at a gain of 20%. At what gain percent must he sell the Three-fourth of books to get a gain of 25% on the whole?
एक आदमी ने 8000 मूल्य की पुस्तकें खरीदीं और उनमें से एक-चौथाई को 20% के लाभ पर बेचा. सभी पर 25% का लाभ पाने के लिए उसे तीन-चौथाई पुस्तकों को किस लाभ प्रतिशत पर बेचना चाहिए.
(a) 26.66%
(b) 25%
(c) 20%
(d) 26%

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Q6. The ratio of man’s age and his son’s age is 4:1 and the product of their ages is 1024. The ratio of their ages after 4 years will be
आदमी की आयु और उसके पुत्र की आयु का अनुपात 4: 1 है और उनकी आयु का गुणनफल 1024 है. 4 वर्ष बाद उनकी आयु का अनुपात होगा:
(a) 5:17
(b) 17:5
(c) 5:7
(d) None of these/ इनमें से कोई नहीं

Q7. If the arithmetic mean of 80 numbers is calculated, it is 40. If each number is decreased by 4, then average of new number is
यदि 80 संख्याओ के अंकगणितीय माध्य की गणना की जाए तो यह 40 है. यदि प्रत्येक संख्या को 4 से घटाया जाए, तो नई संख्या का औसत होगा:
(a) 44
(b) 36
(c) 32
(d) None of these/ इनमें से कोई नहीं

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Q10. If x is an even integer, then which is true?
यदि x एक सम पूर्णांक है, तो कौन-सा सही है?
(a) 5x-2 is odd/ 5x-2 विषम है
(b) 4x+2 is odd/ 4x+2 विषम है
(c) 6x+3 is odd/ 6x+3 विषम है
(d) None of these/ इनमें से कोई नहीं

Solutions

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S6. Ans.(b)
Sol. man:son
          4   :   1
Product of man’s age and son’s age = 1024
4x×1x= 1024
4x²= 1024
x²=256
 x=16
man’s age= 4×16=64
son’s age= 1×16= 16
ratio of their ages after 4 years
= 64+4: 16+4
=  68:20
 = 17:5

S7. Ans.(b)
Sol. mean of 80 numbers = 40
After each number decreased by 4
= 40-4
New average= 36

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S10. Ans.(c)
Sol.


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