Important Mathematics Questions for CTET 2020 : 5th February 2020

Q1. The value of (6.5×7.25+8.5×19.5+4.5-8.5)
(6.5×7.25+8.5×19.5+4.5-8.5) का मान होगा?
(a) 270
(b) 208.875
(c) 270.55
(d) None of these/ इनमें से कोई नहीं

Q3. 13 + 46 – 167+75 + x= 176
(a) 207.190
(b) 207
(c) 209
(d) 209.195

(a) 51.42
(b) 55.65
(c) 56
(d) None of these/ इनमें से कोई नहीं

Q7. {4+1 [ 4 -6 (4-4+6) + 6 ] -6 }
(a) -28
(b) 28
(c) 24
(d) None of these/ इनमें से कोई नहीं

Q8. [(2.6×4)÷1]-[(2.4×6)÷2]+[(2.2×8)÷4]
(a) 7.6
(b) 7.2
(c) 7
(d) 1

(a) 2
(b) 0.5
(c) 1
(d) 0

Q10. 0.5+0.3×0.25+8 ×0.5+16
(a) 0.55
(b) 21
(c) 21.25
(d) All are equal/ सभी समान हैं

Solutions

S1. Ans.(b)
Sol. (6.5×7.25+8.5×19.5+4.5-8.5)
= 47.125+165.75+4.5-8.5
= 217.375-8.5
= 208.875

S3. Ans.(c)
Sol. Solve according to BODMAS
13 + 46 – 167+75 + x= 176
134 – 167 + x =176
-33 + x =176
x= 209

S7. Ans.(a )
Sol. {4+1 [ 4 -6 (4-4+6) + 6 ] -6 }
= {4+1 [ 4 -6 (6) + 6 ] -6 }
={4+1 ( 4 -36 + 6 ) -6 }
=(4 -26-6)
= -28

S8. Ans.(a)
Sol. [(2.6×4)÷1]-[(2.4×6)÷2]+[(2.2×8)÷4]
= (10.4÷1)-(14.4÷2)+(17.6÷4)
= 10.4-7.2+4.4
= 14.8-7.2
= 7.6

S10. Ans.(c)
Sol. 0.5+0.3×0.25+8 ×0.5+16
=0.5 + 0.75 + 4 + 16
=21.25

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