
CTET/ UPTET Exam Practice Mathematics Questions-
Dear Students!!! There is most general as well as a scoring section in all the competitive entrance examinations in the teaching field i.e “Mathematics”.Because in this section only one thing is work i.e your accuracy and that could be nourished with the daily practice.With proper system, Study Notes, Quizzes, Vocabulary one can quiet his/her nerves and exceed expectations in the blink of an eye. So, for this, we are providing you the daily quiz for all teaching exams i.e CTET Exam 2019, DSSSB ,KVS,STET Exam.
Q1. The radius of a circle is 6 cm and the length of one of its chords is 6 cm. Find the distance of the chord from the Centre.
(a) 3 cm
(b) 3√3 cm
(c) 10 cm
(d) 5 cm
Q2. In the figure, find ∠PQB, where O is the Centre of the circle.
(a) 48°
(b) 50°
(c) 60°
(d) 40°
Q3. On the basis of the following three form of a dice, determine the value of ‘?’
(a) 4
(b) 3
(c) 5
(d) 6
Q4. In a circle of radius 17 cm, two parallel chords are drawn on opposite side of a diameter. The distance between the chords is 23 cm. If the length of one chord is 16 cm, then the length of the other is
(a) 34 cm
(b) 15 cm
(c) 23 cm
(d) 30 cm
Q5. In the adjoining figure, POQ is the diameter of the circle, R and S are any two points on the circle. Then,
(a) ∠PRQ>∠PSQ
(b) ∠PRQ<∠PSQ
(c) ∠PRQ=∠PSQ
(d) ∠PRQ=1/2∠PSQ
Q6. In the adjoining figure, ∆ABC is an isosceles triangle with AB=AC and ∠ABC=50°. Then, ∠BDC is equal to
(a) 110°
(b) 90°
(c) 80°
(d) 70°
Q7. If O is the Centre of the circle, then X is equal to
(a) 72°
(b) 62°
(c) 82°
(d) 52°
Q8. The values of x and y in the figure are measure of angles, then x+y is equal to
(a) 90°
(b) 85°
(c) 75°
(d) 65°
Q9. If O is the Centre of circle, the value of x in the adjoining figure, is
(a) 80°
(b) 70°
(c) 60°
(d) 50°
Q10. In the given figure, O is cnetre, then ∠ACB is equal to
(a) 60°
(b) 120°
(c) 75°
(d) 90°
Solutions
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