Dear Students!!! There is most general as well as a scoring section in all the competitive entrance examinations in the teaching field i.e “Mathematics”.Because in this section only one thing is work i.e your accuracy and that could be nourished with the daily practice. So, for this, we are providing you the daily quiz for all teaching exams i.e CTET Exam 2018, DSSSB Exam & amp; STET Exams.

*Q1. A and B can finish a job in 12 days; B and C in 15 days and C and A in 20 days. Working alone C can finish the job in*
(a) 60 days

(b) 90 days

(c) 108 days

(d) 12 days

*Q2. A can do a job in 24 days. B is 50% more efficient than A. Then B can finish the job in*
(a) 16 days

(b) 12 days

(c) 18 days

(d) 10 days

**Q3. A can do twice as much work as B. If they can together finish the job in 24 days, then working alone A would have finished the job in**
(a) 72 days

(b) 42 days

(c) 36 days

(d) 121 days

*Q4. 3 men or 5 women can reap a field in 43 days. Time needed by 5 men and 6 women to do the same is*
(a) 7.5days

(b) 15 days

(c) 16 days

(d) 30 days

*Q5. If 3 men or 4 women can do a piece of work in 43 days, then time needed by 7 men and 5 women to do the same work is*
(a) 18 days

(b) 16 days

(c) 12 days

(d) 20 days

**Q6. 30 men and 14 boys can reap a field in 21 days. If 3 men do as much work as 5 boys then 20 men and 4 boys will finish the work in**
(a) 18 days

(b) 27 days

(c) 26 days

(d) None of above

*Q7. If A takes half as long to do a piece of work as B takes and if C does it in same time as A and B together, and if all three working together will take 7 days to complete the work then B working alone would finish the job in*
(a) 21 days

(b) 14 days

(c) 42 days

(d) 12 days

**Q8. A can do as much work in 3 days as C in 4 days and B can do as much work in 5 days as C in 6 days. Time needed by B to finish a work which A can finish in 18 days in**
(a) 20 days

(b) 10 days

(c) 15 days

(d) 24 days

**Q9. A can finish a job in 15 days and B can do it in 10 days. If they work together then A’s share out of total wages of Rs. 2250 is**
(a) Rs. 1350

(b) Rs. 900

(c) Rs. 1025

(d) Rs. 1125

*Q10. A can do a piece of work in 8 days and B can do the same work in 12 days. A and B together complete the job and get Rs. 200 as combined wages. B’s share in the wage will be*
(a) Rs. 80

(b) Rs. 80

(c) Rs. 85

(d) Rs. 75

**Solutions**

**S1. Ans.(a)**

Sol.

1/a + 1/b = 1/12

1/b + 1/c = 1/15

1/c + 1/a = 1/20

2(1/a + 1/b + 1/c) = 1/5

⇒1/a + 1/b + 1/c = 1/10

1/c = 1/10 – (1/a + 1/b) = 1/10 – 1/12 = 1/60

⇒ time = 60 days

**S2. Ans.(b)**

Sol. B needs half the time

⇒ B needs 24 × 1/2 = 12 days

**S3. Ans.(c)**

Sol.

1/x + 1/2x = 1/24

⇒3/2x = 1/24

⇒ x = 36

Hence A requires 36 days.

**S4. Ans.(b)**

Sol. Work done by 1 man in 1 day = 1/(3 × 43) = 1/129

Work done by 1 women in 1 day = 1/(5 × 43) = 1/215

Work done by 5 men and 6 women in 1 day

=5/129 + 6/215 = 1/15

Hence work will be over in 15 days

**S5. Ans.(c)**

**S6. Ans.(d)**

Sol.

30/m + 40/b = 1/21 …(i)

3×1/m = 5×1/b

⇒1/m = 5/3b

Substituting in (i)

We get 1/b = 1/1050 and 1/m = 1/630

Work done by 20 men and 4 boys in 1 day

=20/630 + 4/1050 = 13/315

Hence work will be over in 315/13 = 243/13 days

**S7. Ans.(c)**

Sol.

1/c = 2/x + 1/x = 3/x

1/a + 1/b + 1/c = 2/x + 1/x +3/x = 6/x = 1/7

⇒ x = 42

⇒ time = 42 days

**S8. Ans.(a)**

Sol.

3/a = 4/c and 5/b = 6/c

⇒3/4a = 1/c and 5/6b = 1/c

⇒3/4a = 5/6b

but 1/a = 1/18

⇒1/b = 3/4 × 1/18 × 6/5 = 1/20

⇒ b needs 20 days to finish the work

**S9. Ans.(b)**

Sol. A : B = 1/15 : 1/10 = 10 : 15

A’s share = 10/(10 + 15) × 2250 = 900

**S10. Ans.(a)**

Sol. A : B = 1/8 : 1/12 = 12 : 8

B’s share = 8/(12 + 8) × 200 = 80