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# CTET Scoring Mathematics Questions | Important Study Material

Dear Students!!! There is most general as well as a scoring section in all the competitive entrance examinations in the teaching field i.e “Mathematics”.Because in this section only one thing is work i.e your accuracy and that could be nourished with the daily practice. So, for this, we are providing you the daily quiz for all teaching exams i.e CTET Exam 2019DSSSB ,KVS,STET Exam.

Q1. 0.46 × 0.46 + 0.54 × 0.54 + 0.92 × 0.54 is equal to
(a) 1
(b) 10
(c) 11
(d) 101

Q2. What will come in place of question mark (?) (17.28 ÷ ?)/(3.6 × 0.2) = 2
(a) 120
(b) 1.20
(c) 12
(d) 0.12

Q3. A number when tripled and decreased by 15 we get the result as 120. Find the number.
(a) 45
(b) 40
(c) 42
(d) 50

Q4. Three solid spheres of radii 3 cm, 4 cm and 5 cm respectively are melted and made a large solid sphere. Radius of this sphere is
(a) 12
(b) 10
(c) 6
(d) 4

Q5. How many lines of symmetry does a Rhombus have?
(a) 1
(b) 2
(c) 3
(d) 4

Q7. What is the area of an equilateral triangle of side 16 cm?
(a) 48√3 sq cm
(b) 128√3 sq cm
(c) 9.6√3 sq cm
(d) 64√3 sq cm

Q8. Find the median of the data
10, 8, 5, 3, 9, 6, 12, 14, 13, 7, 1
(a) 8
(b) 10
(c) 9
(d) 14

Q9. The expression x² – 2xy + y² – x + y has one factor which is
(a) x – y + 1
(b) x + y – 1
(c) x – y – 1
(d) x + y + 1

Q10. A man covers 9/20  by bus and the remaining 10 km on foot. His total journey (in km) is
(a) 15.6
(b) 24
(c) 18.18
(d) 12.8

Solutions:

S1. Ans.(a)
Sol. Given expression can be written as
0.46² + 0.54² + 2 × 0.46 × 0.54
= (0.46 + 0.54)² = 1

S2. Ans.(c)
Sol. 17.28 ÷ ? = 2 × 3.6 × 0.2
i.e., 17.28/? = 1.44 = 1.2²
⇒(1.728×10)/?= (1.2)²
⇒[(1.2)³×10]/?=(1.2)²
⇒ ? = 12

S3. Ans.(a)
Sol. 3x – 15 = 120 ⇒ x = 45

S4. Ans.(c)
Sol. Volume of new sphere
=4/3 π(3³+4³+5³)
=4/3 π(27+64+125)
=4/3 π(216)=4/3 π6³

S5. Ans.(b)
Sol.

A rhombus has two lines of symmetry joining its opposite vertices.

S7. Ans.(d)
Sol. Required area
=√3/4 a²=√3/4×(16)²=64√3  cm².

S8. Ans.(a)
Sol. Arrange the data in ascending order 1, 3, 5, 6, 7, 8, 9, 10, 12, 13, 14
Median = Middle observation = 8

S9. Ans.(c)
Sol. x² – 2xy + y² – x + y = (x – y)² – (x – y)
= (x – y) (x – y – 1)

S10. Ans.(c)
Sol. Total distance = D
11D/20=10
11D = 200
D=200/11
D = 18.18