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# Maths Questions for CTET,KVS Exam : 20th september 2018

Dear Students!!! There is most general as well as a scoring section in all the competitive entrance examinations in the teaching field i.e “Mathematics”.Because in this section only one thing is work i.e your accuracy and that could be nourished with the daily practice. So, for this, we are providing you the daily quiz for all teaching exams i.e CTET Exam 2018, DSSSB ,KVS,STET Exam. Q2. Write the additive inverse of (-2)/17.
(a) 2/17
(b) 2/(-17)
(c) 17/2
(d) (-17)/(-2)

Q3. The product of two whole numbers is 24. The smallest possible sum of these numbers is
(a) 8
(b) 9
(c) 10
(d) 12

Q4. Ascending order of numbers 1278, 1279, 10001 and 9871 is
(a) 1278, 1279, 10001, 9871
(b) 1279, 1278, 10001, 9871,
(c) 9871, 1278, 1279, 10001
(d) 1278, 1279, 9871, 10001

Q5. What should be subtracted from (-5)/7 to get –1?
(a) (-2)/7
(b) 4/7
(c) 2/7
(d) (-4)/7

Q6. Which number is the Identity for the addition of whole numbers?
(a) 0
(b) 10
(c) 1
(d) 100

Q7. The value of √(16√(8√4) ) is
(a) 16
(b) 8
(c) 8∛2
(d) 16√2

Q8. Subtract 3/4 from 5/6.
(a) 1/12
(b) 2/12
(c) 3/6
(d) 12/1

Q9. The value of ∛500×∛16 is
(a) 16
(b) 20
(c) 25
(d) 18

Q10. Which of the following is unit fraction?
(a) 1/11
(b) 11/11
(c) 3/5
(d) 111/11

Solutions S2. Ans.(a)
Sol. Additive inverse means the same number with an opposite sign.
Therefore additive inverse of (-2)/17 is 2/17.

S3. Ans.(c)
Sol.
Factors of 24 Sum of factors
1, 24               1 + 24 = 25
2, 12               2 + 12 = 14
3, 8                 3 + 8 = 11
4, 6                 4 + 6 = 10
The smallest sum is 10.

S4. Ans.(d)
Sol. After arranging the numbers from the lowest to the highest, we have 1278 < 1279 < 9871 < 10001

S5. Ans.(c)
Sol. Let x be subtracted from (-5)/7 to get –1.
∴ (-5)/7-x=-1
⇒(-5)/7+1=x
⇒(-5+7)/7=x
∴x=2/7

S6. Ans.(a)
Sol. As a + 0 = 0 + a = a, where ‘a’ is a whole number, 0 is the additive identity.

S7. Ans.(b)
Sol. √(16√(8√4) )
=√(16√(8×2))
=√(16√16)
=√(16×4)
=√64
= 8

S8. Ans.(a)
Sol.
5/6-3/4=(10 – 9)/12=1/12

S9. Ans.(b)
Sol. ∛500×∛16
=∛(500×16)
=∛(2×2×5×5×5×2×2×2×2)
=∛((2×2×2)×(2×2×2)×(5×5×5) )
= 2 × 2 × 5 = 20

S10. Ans.(a)
Sol. The fraction whose numerator is one is a unit fraction. Join India's largest learning destination

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