1. Jagtap purchases 30 kg of wheat at the rate of Rs. 11.50 per kg and 20 kg of wheat at the rate of Rs. 14.25 per kg. He mixed the two and sold the mixture. Approximately at what price per kg should he sell the mixture to make 30 percent profit?
(a) Rs. 16.30
(b) Rs. 18.20
(c) Rs. 15.60
(d) Rs. 14.80
Sol.
Cost price of mix=30×11.50+20×14.25/20+30=12.6
Selling price =12.6×1.3=16.30
2. A container contains 10 litres mixture in which there is 10% sulphuric acid. How much sulphuric acid is to be added to make the solution to contain 25% sulphuric acid?
(a) 2 litres
(b) 1 litre
(c) 4 litres
(d) Data inadequate
Sol.
Initially container contains sulphuric acid=1 litres
And water=9litres
Let the X litres sulphuric acid dded
According to question=1+X=(10+X) ×.25
So, X=2 litres
3.Three students A, B and C play cricket. The runs scored by A and B respectively are in the ratio 3 : 2. B’s runs to C’s runs are also in the same ratio. Together they score 342 runs. Then the runs scored by B are
(a) 216
(b) 108
(c) 90
(d) 171
Sol.
A : B = 3 : 2 = 9 : 6
B : C = 3 : 2 = 6 : 4
so A : B : C = 9 : 6 : 4
so Runs scored by B = 6/19 * 342
= 108
4. A father is 7 years older than the mother and the mother’s age now is 3 times the age of the daughter. The daughter is 10 years old now. What was the father’s age when the daughter was born?
(a) 27 years
(b) 37 years
(c) 15 years
(d) 40 years
Sol.
Mother’s present age
= 30 years
Father’s present age = 37 year
5. A person borrowed a sum of Rs. 20000 for two years on simple interest. He had to repay Rs. 24800 including interest after two years. The rate of interest per annum was
(a) 48%
(b) 24%
(c) 12%
(d) 6%
Sol.
Amount = Rs. 24800
Principal = Rs. 20000
∴ SI = (Amount – Principal) = 24800 – 20000 = Rs. 4800
Rate of interest = (SI × 100)/(P × T)=(4800 ×100)/(20000 ×2)=12%
6. X can do a piece of work in 20 days and Y can do it in 10 days. They started together, but after 6 days X leaves off. Y will do the rest work in
(a) 1 day
(b) 2 days
(c) 7/3 days
(d) 3 days
Sol.
(X + Y)’s 6 days’ work = 6 * (1/20 + 1/10) = 9/10
Remaining work = 1 – 9/10 = 1/10
1/10 work is done 2y Y in 10 * 1/10 = 1 day
7. If each side of a rectangle is increased by 50%, its area will increase by
(a) 125%
(b) 75%
(c) 100%
(d) 225%
Ans. (a)
Sol.
Original area = l × b
New area =3/2 l×3/2 b=9/4 lb
Increase % =(9/4 lb – lb)/lb×100%
= 125%
8. If x^2+1/x^2 =34, then find the value of x+1/x
(a) 4
(b) 6
(c) 8
(d) 17
Sol.
x^2+1/x^2 =34
⇒ (x+1/x)^2-2×1/x=34
[a^2+b^2=(a+b)^2=2ab]
⇒ (x+1/x)^2=36
⇒ x+1/x=6
9. The value of 5-(2 1/2-3/4)+(3 1/2-1 1/4) is
(a) 4 1/2
(b) 5 1/2
(c) 5 1/4
(d) 3 1/2
Sol.
5-[5/2-3/4]+[7/2-5/4]=5-[(10 – 3)/4]+[(14 – 5)/4]=5-7/4+9/4
=(20 – 7 + 9 )/4=22/4=11/2=5 1/2
10. One-fourth of a pizza was eaten by Renu. The rest was equally distributed among 12 children. What part of the pizza did each of these children get?
(a) 1/16
(b) 1/32
(c) 3/16
(d) 1/8
Sol.
Pizza remaining = 3/4
Pizza that single child get = (3/4) × (1/12)=1/16
