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# Maths Quiz For NVS Exam 2016

1.A shopkeeper bought 80 kg of sugar at the rate of Rs.13.5 per kg. He mixed it with 120 kg of sugar costing Rs.16 per kg .In order to make a profit of 20% he must sell the mixture at
(A). Rs.18 per kg
(B). Rs.17 per kg
(C). Rs.16.40 per kg
(D). Rs.15 per kg

2.A seller gains 15% after selling an item at 10% discount on the printed price.The Ratio of the cost price and printed price of the item is
(A). 18 : 23
(B). 17 : 18
(C). 17 : 23
(D). 18 : 25

3.An empty tank can be filled by pipe A in 4 hours and by pipe B in 6 hours .If the two pipes are opened for 1 hour each alternately with first opening pipe A,then the tank will be filled in
(A). 1 3/4 hours
(B). 2 3/5 hours
(C). 4 2/3 hours
(D). 5 1/2 hours

4.Each of side of a rectangular field is diminished by 25 %,By how much percent is the area of the field diminished ?
(A). 46.45
(B). 43.75
(C). 47.5
(D). 44.60

5.Two numbers are 35% and 50% respectively more than a third number.The first number is what percent of the second number ?
(A). 90
(B). 85
(C). 80
(D). 75

6.If A : B = 3 : 4 and B : C = 8 : 9, then the ratio A : B : c is.
(A). 3:4:5
(B). 1:2:3
(C). 7:12:17
(D). 6:8:9

7.If a : b = b : c, then the ratio a^4 : b^4 is equal to
(A). ac:b^2
(B). a^2:c^2
(C). c^2:a^2
(D). b^2:ac

8.The numbers 11284 and 7655, when divided by a certain 3-digits number,give equal remainders. The 3-digit number is
(A). 190
(B). 191
(C). 192
(D). 193

9.Two numbers are in the ratio 5:6.If their LCM is 120 ,their HCF will be
(A). 12
(B). 10
(C). 8
(D). 4

10.A bag contains Rs. 145 in the form of one-rupee,50-paise and 25 paise coins in the ratio 3:5:7.The number of one-rupee coins is.
(A). 60
(B). 50
(C). 48
(D). 45

1.(A)

2.(A)

3.(C) Part of the tank filled in first 2 hours.
1/4 + 1/6 = (3+2)/12 = 5/12 parts
so Part of the tank filled in first 4 hours
= (2*5)/12 parts = 5/6 parts
Remaining part = 1 – 5/6 = 1/6
Now it is the turn of pipe A
Time taken to fill 1/4 part = 1 hour
So Time taken to fill 1/6 part
= 1/6*4 = 2/3 hour
So Total time = 4 + 2/3 = 4 2/3 hours

4.(B)
If the length and breadth of a rectangular are changed by x% and y% respectively
the effective change in area = (x + y + xy/100)%
Here, x = -25. y = -25
so Percentage decrease (-25-25+25*25/100)%
= (-50+6.25)% = -43.75%

5. (A)

6. (D)

7. (B)
a/b = b/c => b^2 = ac
so a^4 : b^4 = a^4 : a^2c^2 = a^2:c^2

8. (B)

9. (D)
5x*6x = 120*HCF
30x^2 = 120*x
x = 4

10. (A)
Ratio of the values of coins = 3/1 : 5/2 : 7/4= 12:10:7
so value of the one rupee coins
= Rs. (12/29*145)= Rs.60 Number of One rupee coins