1.A shopkeeper bought 80 kg of sugar at the rate of Rs.13.5 per kg. He mixed it with 120 kg of sugar costing Rs.16 per kg .In order to make a profit of 20% he must sell the mixture at
(A). Rs.18 per kg
(B). Rs.17 per kg
(C). Rs.16.40 per kg
(D). Rs.15 per kg
2.A seller gains 15% after selling an item at 10% discount on the printed price.The Ratio of the cost price and printed price of the item is
(A). 18 : 23
(B). 17 : 18
(C). 17 : 23
(D). 18 : 25
3.An empty tank can be filled by pipe A in 4 hours and by pipe B in 6 hours .If the two pipes are opened for 1 hour each alternately with first opening pipe A,then the tank will be filled in
(A). 1 3/4 hours
(B). 2 3/5 hours
(C). 4 2/3 hours
(D). 5 1/2 hours
4.Each of side of a rectangular field is diminished by 25 %,By how much percent is the area of the field diminished ?
(A). 46.45
(B). 43.75
(C). 47.5
(D). 44.60
5.Two numbers are 35% and 50% respectively more than a third number.The first number is what percent of the second number ?
(A). 90
(B). 85
(C). 80
(D). 75
6.If A : B = 3 : 4 and B : C = 8 : 9, then the ratio A : B : c is.
(A). 3:4:5
(B). 1:2:3
(C). 7:12:17
(D). 6:8:9
7.If a : b = b : c, then the ratio a^4 : b^4 is equal to
(A). ac:b^2
(B). a^2:c^2
(C). c^2:a^2
(D). b^2:ac
8.The numbers 11284 and 7655, when divided by a certain 3-digits number,give equal remainders. The 3-digit number is
(A). 190
(B). 191
(C). 192
(D). 193
9.Two numbers are in the ratio 5:6.If their LCM is 120 ,their HCF will be
(A). 12
(B). 10
(C). 8
(D). 4
10.A bag contains Rs. 145 in the form of one-rupee,50-paise and 25 paise coins in the ratio 3:5:7.The number of one-rupee coins is.
(A). 60
(B). 50
(C). 48
(D). 45
Answers with Solution:
1.(A)
2.(A)
3.(C) Part of the tank filled in first 2 hours.
1/4 + 1/6 = (3+2)/12 = 5/12 parts
so Part of the tank filled in first 4 hours
= (2*5)/12 parts = 5/6 parts
Remaining part = 1 – 5/6 = 1/6
Now it is the turn of pipe A
Time taken to fill 1/4 part = 1 hour
So Time taken to fill 1/6 part
= 1/6*4 = 2/3 hour
So Total time = 4 + 2/3 = 4 2/3 hours
4.(B)
If the length and breadth of a rectangular are changed by x% and y% respectively
the effective change in area = (x + y + xy/100)%
Here, x = -25. y = -25
so Percentage decrease (-25-25+25*25/100)%
= (-50+6.25)% = -43.75%
5. (A)
6. (D)
7. (B)
a/b = b/c => b^2 = ac
so a^4 : b^4 = a^4 : a^2c^2 = a^2:c^2
8. (B)
9. (D)
5x*6x = 120*HCF
30x^2 = 120*x
x = 4
10. (A)
Ratio of the values of coins = 3/1 : 5/2 : 7/4= 12:10:7
so value of the one rupee coins
= Rs. (12/29*145)= Rs.60 Number of One rupee coins
