**1.A shopkeeper bought 80 kg of sugar at the rate of Rs.13.5 per kg. He mixed it with 120 kg of sugar costing Rs.16 per kg .In order to make a profit of 20% he must sell the mixture at**

**(A). Rs.18 per kg**

(B). Rs.17 per kg

(C). Rs.16.40 per kg

(D). Rs.15 per kg

**2.A seller gains 15% after selling an item at 10% discount on the printed price.The Ratio of the cost price and printed price of the item is**

**(A). 18 : 23**

(B). 17 : 18

(C). 17 : 23

(D). 18 : 25

**3.An empty tank can be filled by pipe A in 4 hours and by pipe B in 6 hours .If the two pipes are opened for 1 hour each alternately with first opening pipe A,then the tank will be filled in**

(A). 1 3/4 hours

(B). 2 3/5 hours

**(C). 4 2/3 hours**

(D). 5 1/2 hours

**4.Each of side of a rectangular field is diminished by 25 %,By how much percent is the area of the field diminished ?**

(A). 46.45

**(B). 43.75**

(C). 47.5

(D). 44.60

**5.Two numbers are 35% and 50% respectively more than a third number.The first number is what percent of the second number ?**

**(A). 90**

(B). 85

(C). 80

(D). 75

**6.If A : B = 3 : 4 and B : C = 8 : 9, then the ratio A : B : c is.**

(A). 3:4:5

(B). 1:2:3

(C). 7:12:17

**(D). 6:8:9**

**7.If a : b = b : c, then the ratio a^4 : b^4 is equal to**

(A). ac:b^2

**(B). a^2:c^2**

(C). c^2:a^2

(D). b^2:ac

**8.The numbers 11284 and 7655, when divided by a certain 3-digits number,give equal remainders. The 3-digit number is**

(A). 190

**(B). 191**

(C). 192

(D). 193

**9.Two numbers are in the ratio 5:6.If their LCM is 120 ,their HCF will be**

(A). 12

(B). 10

(C). 8

**(D). 4**

**10.A bag contains Rs. 145 in the form of one-rupee,50-paise and 25 paise coins in the ratio 3:5:7.The number of one-rupee coins is.**

**(A). 60**

(B). 50

(C). 48

(D). 45

**Answers with Solution:**

*1.(A)*

*2.(A)*

*3.(C) Part of the tank filled in first 2 hours.*

*1/4 + 1/6 = (3+2)/12 = 5/12 parts*

*so Part of the tank filled in first 4 hours*

*= (2*5)/12 parts = 5/6 parts*

*Remaining part = 1 – 5/6 = 1/6*

*Now it is the turn of pipe A*

*Time taken to fill 1/4 part = 1 hour*

*So Time taken to fill 1/6 part*

*= 1/6*4 = 2/3 hour*

*So Total time = 4 + 2/3 = 4 2/3 hours*

*4.(B)*

*If the length and breadth of a rectangular are changed by x% and y% respectively*

*the effective change in area = (x + y + xy/100)%*

*Here, x = -25. y = -25*

*so Percentage decrease (-25-25+25*25/100)%*

*= (-50+6.25)% = -43.75%*

*5. (A)*

*6. (D)*

*7. (B)*

*a/b = b/c => b^2 = ac*

*so a^4 : b^4 = a^4 : a^2c^2 = a^2:c^2*

*8. (B)*

*9. (D)*

*5x*6x = 120*HCF*

*30x^2 = 120*x*

*x = 4*

*10. (A)*

*Ratio of the values of coins = 3/1 : 5/2 : 7/4= 12:10:7*

*so value of the one rupee coins*

*= Rs. (12/29*145)= Rs.60 Number of One rupee coins*