**1. Rahul bought 2 old scooters for rupees 22,000. By selling one at Profit of 10% and other at loss of 12%, he neither gains nor loses. What is the C.P of the 2 scooters, individually?**

**A. 12,000; 10,000**

B. 13,000; 9000

C. 11,000; 11,000

D. 10,500; 11,500

**(Let C.P=y, S.P=22,000(as neither gain nor loss)**

**y × 110/100 +(22,000-y)× 88/100 =22,000**

**11y/10 + 1936000-88y/100 = 22,000**

**22y = 2,64,000 ; y= 12,000**

**C.P= 12,000 and 10,000)**

**2. A shopkeeper loses the S.P of 4 pencils on selling 36 pencils. His loss% –**

A. 12.5%

**B. 10%**

C. 15%

D. 25%

**(Let S.P of 1 pencil= 1 Rs , S.P of 36 pencils= 36 Rs**

**S.P<C.P (as loss) , C.P= 36+4= 40 Rs.**

**L%= (4/40) ×100= 10% )**

**3. If a, b, c are respectively the number of faces, edges and vertices of a pentagonal pyramid, then the value of (a-b+c/2)2 – 2 is-**

A. 2

B. 1.75

**C. -1**

D. -1.5

**(Euler’s rule: F+V-E=2, a+c–b = 2**

**By putting it in question: (2/2)2 – 2 = -1 ans)**

**4. An amount of Rs. 15,000 is distributed among A, B and C in the ratio 4:5:6. What is the share of B?**

**A. 5000**

B. 6000

C. 4000

D. 7000

**(let, share of A=4x, B=5x, C=6x**

**Total amount = A+B+C ; 4x+5x+6x= 15000**

**15x= 15000, x= 1000**

**B’s share(5x) = 5000 Rs)**

**5. Perimeter of a floor of a cuboidal room is 250m. Cost of painting 4 walls at the rate of 10 rupees per square meter is Rs. 15000. What is the height of the room?**

A. 4m

B. 5m

**C. 6m**

D. 7m

**(Area of 4 walls of a room= 2h(l+b)**

**15000/10= h×2(l+b)**

**1500= h×250; h=6m)**

**6. The value of ratio of volume of a sphere to the volume of a cylinder is 2:1 .Find the height of a cylinder-**

A. (1/2)r

B. (6/5)r

C. (3/2 r

**D. (2/3)r**

**(Vol. of sphere/Vol. of cylinder) = (2/1)**

**(4/3)πr3/ πr2h= 2/1**

**(4r/3h)=(2/1); h= (2/3)r )**

**7. The square of 9 is divided by the cube root of 125. The remainder is-**

A. 4

**B. 1**

C. 2

D. 3

**( i.e 81/5… remainder is 1)**

**8. One half of 1.2×10^30 is-**

A. 0.6×530

B. 6.0×1030

**C. 6.0×1029**

D. 1.2×1015

**((1.2×1030)/2= 6.0×1029)**

**9. The number of vertices in a polyhedron which has 30 edges and 12 faces is-**

A. 24

B. 12

C. 15

**D. 20**

**(F+V-E=2; 12+V-30=2**

**V-18=2; V=20)**

**10. When half of a number is increased by 16, the result is 48. The sum of digits of the original number is-**

**A. 10**

B. 11

C. 12

D. 13

**(Let the number be x.**

**(x/2)+16=48**

**X+32=96; x=64**

**Sum= 6+4=10)**