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# Maths Quiz for 2016-17 Exams

1. What is the measure of the angle which is one fifth of its supplementary part?
(a) 15°
(b) 30°
(c) 36°
(d) 75°
Ans. (b); Let required angle be x then its supplementary angle is (180°-x)
According to question,
x=1/5 (180°-x)
5x=180°-x
∴x=(180°)/6=30°

2. Consider the following statements:
If a transversal line cuts two parallel lines then
1. Each pair of corresponding angles are equal.
2. Each pair of alternate angles are unequal.
Among these, true statements are–
(a) Only 1
(b) Only 2
(c) both 1 and 2
(d) Neither 1 nor 2
Ans.(a); Statement (1) is true. Statement (2) is wrong.

3. If each interior angle of a regular polygon is 144°, then what is the number of sides in the polygon?
(a) 10
(b) 20
(c) 24
(d) 36
Ans.(a); ∵ Let number of sides be n
According to question, (n-2)180/n=144
(n-2)5=4n
∴ n=10

4. If sum of external and interior angle at a vertex of a regular polygon is 150°; number of sides in the polygon is
(a) 10
(b) 15
(c) 24
(d) 30
Ans. (c); If number of sides in regular polygon be n then
((2n-4))/n×90°-(360°)/n=150°
((2n-4)×3)/n-12/n=5
(6n-12-12)/n=5
6n-24=5n
∴n=24

5. If sum of internal angles of a regular polygon is 1080°, then number of sides in the polygon is
(a) 6
(b) 8
(c) 10
(d) 12
Ans. (b); Sum of interior angle of a regular polygon of n sides=(2n-4)×90°
∴(2n-4)×90°=1080°
2n-4=1080÷90=12
2n=12+4=16
∴n=16/2=8

6. The ratio of sides of two regular polygon is 1 : 2 and ratio of their internal angle is 2 : 3. What is the number of sides of polygon having more sides?
(a) 4
(b) 8
(c) 6
(d) 12
Ans. (b); Let number of sides in two regular polygon are respectively n and 2n, then their each internal angle are respectively (nπ-2π)/n and (2nπ-2π)/2n
According to question, (((nπ-2π)/n))/(((2nπ-2π)/2n) )=2/3
Or, (n-2)π/(n-1)2π×2=2/3
Or, (n-2)/(n-1)=2/3
Or, 3n-6=2n-2
n=4
∴2n=8

7. In the two regular polygon number of sides are in the ratio 5 : 4. If difference between their internal angles is 6°, then number of sides in the polygon is
(a) 15, 12
(b) 5, 4
(c) 10, 8
(d) 20, 16
Ans. (a) Let number of sides be respectively 5x and 4x.
∴ ((2×5x-4)90°)/5x-((2×4x-4)×90°)/4x=6°
[each interior angle=((2n-4)/n)×90°]
(10x-4)×360°-(8x-4)×450°=20x×6°
(10x-4)×12-(8x-4)15=4x
120x-48-120x+60=4x
x=3
∴ Number of sides are respectively 5 and 12.

8. If each of interior angle of a polygon in double its each exterior angle, then number of sides in the polygon is
(a) 8
(b) 6
(c) 5
(d) 7
Ans. (b); Each internal angle of polygon =[(n-2)180/n]^°
Each exterior angle of polygon=[360/n]^°
According to question,
(n-2)180/n=2×360/n
n-2=4
∴n=6

9. Which the following cannot be measure of an interior angle of a regular polygon?
(a) 150°
(b) 105°
(c) 108°
(d) 144°
Ans. (b); Each interior angle of polygon=(n-2)/n×180°.=60°,
when n=3 ,90°,
when n=4 ,108°,
when n=5,120°,
when n=6 ,135°,
when n=8 ,140°,
when n=9 ,144°
when n=10,150°,
when n=12

10. Number of diagonals in a polygon having 10 sides is
(a) 20
(b) 40
(c) 35
(d) 32
Ans. (c); Since number of diagonals in n sided polygon=n(n-3)/2
For, n=3,
Number of diagonals=(10×7)/2=35