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# Maths Quiz: Paper I and II for CTET Exam

1. HCF of two numbers is 28 and their LCM is 336. If one number is 112, then the other number is :
A. 56
B. 84
C. 98
D. 75
(Product of 2 numbers = LCM ×HCF of 2 numbers
112 × y = 336 × 28
y = 9408/112 ; y = 84 ans)

2. If (2/3)x= 0.6 and 0.02y= 1, then the value of x+y-1
A. 0.92
B. 1.2
C. 50.6
D. 48.8
(x = 0.6×3/2, i.e x= 9/10
Y= 1/0.02 i.e y= 50
∴9/10 + 1/50 = 46/50 i.e 0.92 ans)

3. 50% of (100- 20% of 300) is equal to :
A. 40
B. 130
C. 60
D. 20
{(50/100)×(100- 20/100 ×300)
1/2 × (100-60)
(1/2) × 40 = 20 ans }

4. The sum of all interior angles of a polygon is 1440°. The number of sides of the polygon is :
A. 12
B. 14
C. 10
D. 8
{Sum of all interior angles of a polygon= (n-2)×180°
1440° = (n-2)×180°
∴Number of sides(n)= 10 ans}

5. If for ∆PQR and ∆MNO, the correspondence RPQ ↔NMO gives a congruence, then which of the following is not true?
A. PQ= MO
B. RP= MN
C. PR= MN
D. RQ= NO
(RP=NM is correct)

6. The base of an isosceles ∆ABC is 48 cm and its area is 168 cm2. Find its two similar sides:
A. 8 cm
B. 16 cm
C. 25 cm
D. 20 cm
{Ar. of an isosceles ∆ = b/4 ×(4a2-b2)1/2
168= 48/4 ×(4a2- 482)1/2
a2= 625; a= 25 cm }
7. The mean of 10 numbers is 0. If 72 and -12 are included in these numbers, the new mean will be :
A. 5
B. 70
C. 16
D. 0
{(x1+x2+……+x10)/10=0 ;i.e (x1+x2+……+x10) = 0
((x1+x2+……+x10)+ 72-12)/12
∴0+60/12  ; 5 ans}

8. PQRS is a square with PQ= (x+16) cm and QR= (3x) cm. The perimeter of the square is :
A. 16
B. 32
C. 18
D. 28
{Since all sides of a square are equal.
∴x+16= 3x i.e x=8 cm
Perimeter= 4×side i.e 32 cm }

9. The number of integers less than -5 but greater than -11 is :
A. 6
B. 7
C. 4
D. 5
( -6,-7,-8,-9,-10 are 5 integers)

10. The reciprocal of (-6/15) × (-20/24) is :
A. (1/3)
B. (3/1)
C. (4/5)
D. (3/5)
{(-6/15) × (-20/24) = (1/3)
∴reciprocal=(3/1) ans }