1.If a sum is lent at 5% compound interest per annum for 2 year. What is the ratio of the amount to the principal?
A.441:400
B.442:399
C.399:400
D.None of these
Sol: A=P(1+r/100)x
=P(1+5/100)2
=P×441/400
A:P=441:400
2.A number when added to its two thirds is equal to 35. Find the number
A.19
B.20
C.21
D.22
Sol: Let the number be X
Then, According to the question,
X+2/3X=35
=3x+2x/3=35
=5x/3=35
=5x=35×3
=x=35×3/5=21
3.Rs.770 have been divided among A,B and C in such a way that A receives 2/9th of what B and C together receive. Then A’s share is Rs-
A.140
B.154
C.165
D.70
Sol: Given, A=(2÷9)(B+C)
A:B+C= 2:9
A’s part=(770×2/11)=Rs 140
4.The difference between the highest and lowest five digits number using 0,3,6,8 and 9 digits (each digit using once time)-
A.94941
B.61821
C.61740
D.67941
Sol: Largest number of 5 digits= 98630
Smallest digit of 5 digits=30689
Hence, required difference=98630-30689=67941
5.When a number is divided by 387, the remainder obtained is 48. If the same number is divided by 43, then the remainder obtained will be-
A.0
B.3
C.5
D.35
Sol: Suppose quotient=k
Then, number= 387 k+48
= (43×9k+43)+5=43(9k+1)+5
Hence, we divided this number by 43, remainder=5
6.The sum of the greatest and smallest 4 digit numbers is-
A.8999
B.10999
C.11110
D.111111
Sol: The greatest 4 digit number= 9999
The smallest 4 digit number= 1000
Total=10999
7.The area of square, whose perimeter is 48 m is-
A.48 m^2
B.144 m^2
C.1152 m^2
D.2304 m^2
Sol: Side of the square=Perimeter/4
=48/4=12m
Area of the square=Side× Side
=12×12=144 m^2
8.What is the percentage of 500gm is 4 kg?
A.12.5%
B.25%
C.50%
D.125%
Sol: 1 kg =1000gm
4kg= 4×1000gm
=4000gm
Hence required percentage=500×100/4000=12.5%
9.60% of that the students in a school are boys. If the number of girls in the school is 300, then the number of boys is-
A.300
B.450
C.500
D.750
Sol: Here 40% are girl in a school.
40%=300
60%=300× 60/40
=450
10.What should be taken out of 3/7 to get 2/7?
A.5/7
B.1
C.1/7
D.3/7
Sol: Let x be taken out.
Then 3/7-x=2/7
X=3/7-2/7
=1/7
