If n be any natural number, then by which greatest number is (n³ - n) always divisible?

Correct option is A

Given :

n = any natural number

Solution :

Let take n = 1 then :

(n3 - n) = 0

take n = 2 then :

(n3 - n) = 8 - 2 = 6

take n = 3 then :

(n3 - n) = 27 - 3 = 24

From above results we can say that the greatest number is 6 by which (n3 - n) is always divisble if n is any natural number.

Hence the correct answer is "6".