UPRVUNL JE Recruitment 2021: Uttar Pradesh Rajya Vidyut Utpadan Nigam Limited (UPRVUNL) has released a short notice for the post of Junior Engineer (Trainee) Electrical, Electronics & Instrumentation, Mechanical, and Computer on 16th March 2021 on its official website. The official notification has been released. A total of 196 vacancies released by the UPRVUNL Recruitment 2021. The online registration ended on 05th May 2021.
official website – uprvunl.org.
UPRVUNL-JE ELECTRICAL-2021 QUIZ
Each question carries 1 mark.
Negative marking: 1/4 mark
Total Questions: 06
Time: 06 min.
Q1. The critical temperature at which high ferromagnetic materials lose their magnetism is called
(a) Curie Point
(b) Hysteresis
(c) Transition temperature
(d) Standard temperature
Q2. The rating of a battery is expressed in
(a) Ampere-Hour
(b) Watt-Hour
(c) Amperes
(d) Watts
Q3. There are _______ slip rings in a squirrel cage induction motor.
(a) 2
(b) 4
(c) 3
(d) 0
Q4. The number of secondary turns of a coil in a transformer is 4 times the numbers of turns in the primary coil. If the voltage in primary coil is 200 V, the secondary voltage would be
(a) 2000 V
(b) 200 V
(c) 800 V
(d) 50 V
Q5. An RLC series circuit remains predominantly inductive
(a) At resonance frequency
(b) Below resonance frequency
(c) Above resonance frequency
(d) Any of the above
Q6. The X/R ratio of 220 kV line as compared to 400 kV line is
(a) Greater
(b) Smaller
(c) Equal
(d) None of the above
SOLUTIONS
S1. Ans.(a)
Sol. The Curie temperature (T_C), or Curie point, is the temperature above which certain materials lose their permanent magnetic properties, to be replaced by induced magnetism.
If a ferromagnetic material has a temperature over its Curie temperature, then the material becomes paramagnetic or does not become a magnet.
S2. Ans.(a)
Sol. Battery capacity = charge stored = current x time or amp-hr.
S3. Ans.(d)
Sol. squirrel cage induction motor:
In squirrel cage induction motor, the rotor bars are permanently short-circuited by end rings and there are no slip rings
So, it is not possible to connect an external resistance in the circuit in series with the rotor conductors.
S4. Ans.(c)
Sol. ACQ: N_2=4N_1⇒N_2/N_1 =4
∴V_2/V_1 =N_2/N_1
⇒V_2=V_1×N_2/N_1 =200×4=800 V
S5. Ans.(c)
Sol. An RLC series circuit:
Capacitive in nature below resonant frequency
Inductive in nature above resonant frequency
Vice-versa for RLC parallel circuit
S6. Ans.(b)
Sol. X depends on the equivalent distance between phases (which increases at higher voltages) and the GMR of the conductor. so, we have (X/R) ratio as high as 10 -15 for a 400 kV line.
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