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RSMSSB-JE’21 CE: Daily Practices Quiz. 23-July-2021

Quiz: Civil Engineering
Exam: RSMSSB-JEn
Topic: Miscellaneous

Each question carries 1 mark
Negative marking: 1/3 mark
Time: 8 Minutes

Q1. The true length of a line is known to be 200 m. When this is measured with a 20 m tape, the length is 200.80 m.
What is the correct length of the 20 m tape?
(a) 19.98 m
(b) 20.08 m
(c) 20.04 m
(d) 19.92 m

Q2. Calculate the capitalized value of a building having annual rent of Rs. 20,000 and highest rate of interest is 5%
(a) 1000
(b) 21000
(c) 220000
(d) 400000

Q3. The portion of the brick without a triangular corner equal to half the width and half the length is called ………..
(a) Closer
(b) Queen closer
(c) King closer
(d) Squint brick

Q4. According to IS 399-1963, the weight of the timber is to be recommended at a moisture content of ________.
(a) 4%
(b) 12%
(c) 8%
(d) 5%

Q5. For a given soil sample,
C_c= Coefficient of curvature
C_u = Coefficient of uniformity
D_10 = Effective size
D_30= Diameter through which 30% of the total soil mass is passing
If C_c=1.0 and C_u=4.0, then what would be the value of D_30 \/D_10 ?
(a) 2.00
(b) 1.25
(c) 1.50
(d) 1.75

Q6. The moment of inertia of a hollow circular section whose external diameter is 8 cm and internal diameter is 6 cm about centroidal axis is _______
(a) 437.5 cm^4
(b) 337.5 cm^4
(c) 237.5 cm^4
(d) 137.5 cm^4

Solutions

S1. Ans.(d)
Sol. Given, True length of line (L) = 200 m.
True length of Tape (l) = 20 m.
Wrong length of line (L’) = 200.80m.
Actual length of Tape (l’) =?
L × l = L’ × l’
200 × 20 = 200.8 × l’
▭(l^’=19.92 m.)

S2. Ans.(d)
Sol. Annual rent (R) = 20,000
Year purchase (Y.P) = 100/(i%)
= 100/5
▭(Y.P=20)
Capitalized value = Annual rent × Year’s Purchase
= 20,000 × 20
= 400,000 Rs.

S3. Ans.(c)
Sol. The portion of the brick without a triangular corner equal to half the width and half the length is called king closer.

RSMSSB-JE'21 CE: Daily Practices Quiz. 23-July-2021 |_30.1

S4. Ans.(b)
Sol. Seasoning is the process of adjusting the moisture content of wood or remove the sap from the wood. The moisture content in a well-seasoned timber is about 10-12%
Objective of seasoning →
– Reduce the weight
– Reduction in Shrinkage and warping.
– Increase in strength and durability.
– Remove sap.
– Reduce the tendency of split and decay.

S5 Ans.(a)
Sol. C_c=1 C_u=4
(D_30 )^2/(D_60 D_10 )=1–(1) D_60/D_10 =4–(2)
Multiply both eq^n
(D_30/D_10 )^2=4 ⇒ ▭(D_30/D_10 =2)

S6. Ans.(d)
Sol. Moment of inertia of follow circular section
I=π/64 ( d_O^4-di_O^4 )
=π/64 (8^4-6^4 )
=137.44 cm^4

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