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# RSMSSB-JE’21 CE: Daily Practices Quiz. 13-Aug-2021

Quiz: Civil Engineering
Exam: RSMSSB-JEn
Topic: Miscellaneous

Each question carries 1 mark
Negative marking: 1/3 mark
Time: 8 Minutes

Q1. Which of the following defect appears due to presence of alkalis in the bricks?
(a) Bloating
(b) Black core
(c) Crackers
(d) Efflorescence

Q2. A building is fetching an annual rent of Rs. 1,80,000/-. The purchases desires to get 5% return on the capital. The capitalized value (in Rs) of the building is:
(a) 9,00,000
(b) 27,00,000
(c) 36,00,000
(d) 18,00,000

Q3. The back sight taken on a B.M. (R.L. = 500.000m.) was 3.415 m. The fore sight taken on the next point (a) was 2.125m. The R.L. of point A will be:
(a) 503.415 m
(b) 502.125 m
(c) 505.540 m
(d) 501.290 m

Q4. In slow sand filters, the rate filtration is –
(a) 100 to 200 litres/ hours per. sq. m. of filter area
(b) 200 to 300 litres/ hour per. sq. m. of filter area
(c) 100 to 200 litres/ hour per. sq. m. of filter area
(d) 200 to 300 litres/ hour per. sq. m. of filter area

Q5. The average value of co-efficient of velocity is
(a) 0.84
(b) 0.76
(c) 0.97
(d) 0.62

Q6. For slabs spanning in two directions the ratio of span to depth should not exceed:
(a) 15
(b) 25
(c) 35
(d) 50

Solutions

S1. Ans.(d)
Sol. Defects in bricks-
Efflorescence→ This defect appears in bricks due to the presence of alkalis in the bricks.
Chuffs → This is the defect in bricks in which shape of the bricks gets deformed due to rain water falling on hot brick.
Bloating → Bloating of bricks is swollen spongy mass over the surface of burned bricks.
Black core→ The brick converts in black core because of improper burning.

S2. Ans.(c)
Sol. Given, rate of interest (i) = 5%
Annual rent = 1,80,000 Rs.
Capitalized value =?
Year’s purchase = 100/(i%)=100/5=20 years
Capitalized value of building = Annual rent × year’s purchase
= 1,80,000 × 20
= 36,00,000 Rs

S3. Ans.(d)
Sol. Given, BM = 500.00 m. (R.L)
BS = 3.415 m
FS at point A = 2.125 m.
RL of point A = ?
H.I = RL of BM + BS
= 500 + 3.415
= 503.415 m.
R.L at point ‘A’ = H.I – FS
= 503.415 – 2.125
= 501.290 m.

S4. Ans.(a)
Sol. The rate of filtration for slow sand filters is 2400 to 4800 l/day/m² or 100 to 200 l/hour/m².

S5. Ans. (c)
Sol. Velocity (V₁) = C_v √2gh
C_v ⇒ coefficient of velocity
C_v ⇒ 0.97 – 0.99

S6. Ans.(c)
Sol. Slabs spanning in one direction (one way slab)
l/d=30
Slabs spanning in two directions (two-way slab)
l/d<35 (simply supported)
l/d≤40 (continous)

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