As RSMSSB JE exam date 2021 is announced which is going to be held on 12th September 2021. As RSMSSB JE exam date 2021 is nearby so boost your preparation by attempt this Civil Engineering miscellaneous quiz for RSMSSB JE recruitment 2021.
Quiz: Civil Engineering
Each question carries 1 mark
Negative marking: 1/3 mark
Time: 8 Minutes
Q1. Kharif crop sown in
(a) In June
(b) In September
(c) In October-November
(d) None of the above
Q2. Web crippling in beams generally occurs at the point where-
(a) Concentrated load act
(b) Shear force is maximum
(c) Bending moment is maximum
(d) Deflection is maximum
Q3. The value of the property or commodity at the end of the utility period without being dismantled is known as
(a) Scrap value
(b) Fair value
(c) Replacement value
(d) Salvage value
Q4. Which of the following is a sedimentary rock?
Q5. The correction for curvature and combined correction for curvature and refraction for a distance 1,500 m are:
(a) 176 m, 151 m
(b) 176 cm, 151 cm.
(c) 176 mm, 151 mm.
(d) 176 km, 151 km.
Q6. Calculate detention time of the tank whose breadth is 2 m, length is 4 m and depth is 2.5m. the rate of flow is 4 x 10³ liters per hour
(a) 5 hours
(b) 4 hours
(c) 5.5 hours
(d) 2.5 hours
Sol. Kharif crops sown in June and harvested in September and October. The major kharif crops are bajra, maize, cotton, sugarcane, paddy, jowar, rice, pulses, and ground-nut etc.
Sol. A beam is designed to resist maximum bending moment and is checked for shear stress and deflection, and also for web crippling and web buckling. web crippling in beams is generally occur at the point where concentrated load act.
Sol. Types of value
Market value → This is the value of the property when it put for open sale at auction.
Book value → It is the value of property during its life based on purchase value & depreciation etc.
Scrap value → It is the value of dismantle material when design life of structure is completed.
Salvage value → It is the value of property at the end of the utility period without being dismantled.
Sol. Sedimentary rocks → These rocks are formed by deposition of products of weathering on the pre-existing rock by transport agent like frost, rain, wind etc.
Ex. Sandstone, Limestone, Lignite, Gypsum etc.
Sol. Given, d = 1500m = 1.5 km
Correction for curvature (C_C ) = -0.0785 d²
= -0.0785 × (1.5) ²
= -0.176625 m.
= 176 mm. (Negative)
Combined correction (C) = -0.0673 d²
= -0.0673 × (1.5) ²
= 0.151425 m.
= 151 mm. (Negative)
Length (L) = 4m.
Breadth (B) = 2 m.
Depth (D) = 2.5 m.
Discharge (Q) = 4 × 10³ l/hour
Detention time of tank (t_d) =?
t_d = (Volume of tank (V))/(Discharge (Q) )
= (4×2×2.5 (m^3 ))/(4×10^3×10^(-3) (m^3 \/hour) )
= 5 hours.