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RSMSSB-JE’21 CE : Daily Practices Quiz: 08.09.2021

As RSMSSB JE exam date 2021 is announced which is going to be held on 12th September 2021. As RSMSSB JE exam date 2021 is nearby so boost your preparation by attempt this Civil Engineering miscellaneous quiz for RSMSSB JE recruitment 2021.

Quiz: Civil Engineering
Exam: RSMSSB-JEn
Topic: Miscellaneous

Each question carries 1 mark
Negative marking: 1/3 mark
Time: 8 Minutes

Q1. Isopleths are lines on a map through points having equal depth of
(a) Rainfall
(b) Infiltration
(c) Evapotranspiration
(d) Total runoff

Q2. When speed of traffic flow becomes zero, then:
(a) traffic density and traffic volume both attain maximum value
(b) traffic density attains maximum value but traffic volume becomes zero
(c) Traffic density and traffic volume both becomes zero
(d) traffic density becomes zero but traffic volume attains maximum value

Q3. A steel column in a multistoried building carries an axial load of 125 N. it is built up of 2 ISMC – 350 channels connected by lacing. The lacing carries a load of
(a) 125.125N
(b) 12.525N
(c) 3.126 N
(d) Zero

Q4. Calculate the number of bricks in 20 cubic meters brick works.
(a) 500
(b) 1000
(c) 10000
(d) 100000

Q5. Efflorescence in bricks cause due to …………………
(a) excessive burning of bricks
(b) high porosity of bricks
(c) high silt content in brick earth
(d) soluble salts present in clay

Q6. Which of the following Levelling is necessary for carrying Levelling across any obstacle requiring a long sight between two points so situated where no place is there for the setup of the level midway between two points?
(a) Differential Levelling
(b) Fly Levelling
(c) Precise Levelling
(d) Reciprocal Levelling

Solutions

S1. Ans.(c)
Sol. Isopleths are the lines on a map through points having equal depth of “evapotranspiration”. The mean annual potential evapotranspiration (PET) (in cm) over various parts of the country is shown in the form of isopleths.

S2. Ans.(b)
Sol. When speed of traffic flow becomes zero, then traffic density attains maximum value but traffic volume becomes zero.

S3. Ans.(c)
Sol. Axial load = 125 N
Load carrying by lacing member = 2.5 ×125/100
=3.125 N

S4. Ans.(c)
Sol. No. of bricks required in 1m³ volume of brickwork = 500
Hence,
For 20 m³ brickwork, No. of bricks = 500 × 20 = 10000 bricks

S5. Ans.(d)
Sol. Defects in bricks-
Efflorescence→ This defect appears in bricks due to the presence of alkalis in the bricks.
Chuffs → This is the defect in bricks in which shape of the bricks gets deformed due to rain water falling on hot brick.
Bloating → Bloating of bricks is swollen spongy mass over the surface of burned bricks.
Black core→ The brick converts in black core because of improper burning.

S6. Ans.(d)
Sol. Reciprocal levelling → It is done to determined difference in elevations between two points which are situated quite a large distance apart and it is not possible to set up the instrument in between these points.
Ex. Opposite banks of river.

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