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# RSMSSB-JE’21 CE: Daily Practices Quiz. 04-Sep-2021

As RSMSSB JE exam date 2021 is announced which is going to be held on 12th September 2021. As RSMSSB JE exam date 2021 is nearby so boost your preparation by attempt this Civil Engineering miscellaneous quiz for RSMSSB JE recruitment 2021.

Quiz: Civil Engineering
Exam: RSMSSB-JEn
Topic: Miscellaneous

Each question carries 1 mark
Negative marking: 1/3 mark
Time: 8 Minutes

Q1. Which one of the following is the largest scale?
(a) 1 : 500
(b) 1 : 1000
(c) 1 : 2500
(d) 1 : 50,000

Q2. After storage, the strength of cement-
(a) Decrease
(b) Increase
(c) Remains same
(d) May increase or decrease

Q3. The correct relationship between theoretical oxygen demand (TOD), biochemical oxygen demand (BOD) and, chemical oxygen demand (COD) is given by.
(a) TOD > BOD > COD
(b) BOD > COD > TOD
(c) COD > BOD > TOD
(d) TOD > COD > BOD

Q4. Which of the following is the correct sequence of the parts of a canal system?
(a) Head works, distributary and minor
(b) Head works, main canal and minor
(c) Head works, main canal, branch canal, distributary and minor
(d) None of the above

Q5. Minimum pitch of the rivets shall not be less than:
(a) 2.0d
(b) 1.5d
(c) 2.5d
(d) 3.0d

Q6. The ratio between adopted centrifugal ratios for roads and railways is
(a) 3 : 1
(b) 2 : 1
(c) 5 : 1
(d) 4 : 1

Solutions

S1. Ans.(a)
Sol. Arrangement of scale from largest to smallest.
▭(1∶500>1:1000>1∶2500>1∶50,000)
Hence, 1∶500 is the largest scale.

S2. Ans.(a)
Sol. The strength of cement decreases after storage.

 Time Reduction in strength 3 months 6 months 1 year 2 years 10% 20% 40% 50%

S3. Ans.(d)
Sol. The correct relationship between TOD, COD and BOD is
▭(TOD>COD>BOD)

S4. Ans.(c)
Sol. Correct sequence of the parts of a canal system is
Head works → main canal → Branch canal → Distributary → Minor.

S5. Ans.(c)
Sol. Minimum pitch of rivets should be 2.5 times the nominal diameter or rivet i.e. 2.5d.
d = nominal diameter of rivet.

S6. Ans.(b)
Sol.
→ Maximum value of centrifugal ratio for roads = 1/4
→ Maximum value of centrifugal ratio for railways = 1/8
So, ratio between these two = (1/4)/(1/8)
= (2 : 1)

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