Quiz: Electrical Engineering
Exam: AE/JE
Topic: Miscellaneous
Each question carries 1 mark.
Negative marking: 1/4 mark
Time: 10 Minute
Q1. In a 4-pole, 25 KW, 200 V wave wound dc shunt generator, the current in each parallel path will be:
(a) 125 A
(b) 31.25 A
(c) 250 A
(d) 62.5 A
Q2. The power input to a 3-phase induction motor is 50 KW. If the stator losses are 800 W, then copper losses of rotor phase for 0.5 % slip will be:
(a) 492 W
(b) 246 W
(c) 200 W
(d) 100 W
Q3. Determine Thevenin’s equivalent resistance (in ohms) and voltage (V) respectively across terminal x-y for the given electrical circuit –
(a) 12, 40
(b) 20, 80
(c) 10, 30
(d) 10, 50
Q4. The value of current (I) in the following figure is
(a) 3A
(b) 4A
(c) 5A
(d) 6A
Q5. __ should be provided as the working space around the main switchboard according to IE rule 51.
(a) 0.914 m
(b) 0.523 m
(c) 0.638 m
(d) 0.814 m
Q6. A second order control system has a transfer function 16/(s^2+4s+16). Find the settling time for 2% tolerance?
(a) 2 sec.
(b) 5 sec.
(c) 10 sec.
(d) 20 sec.
Q7. The line integral of magnetic field intensity around closed path is equal to current enclosed by path.” This Statement is associated with which law?
(a) Coulomb’s law
(b) Gauss’s law
(c) Ampere’s circuital law
(d) Lenz’s law
Q8. Which of the following is not a Maxwell’s equation?
(a) ∆×E= -∂B/∂t
(b) ∆.E= -B
(c) ∆.D=ρ
(d) ∆.B= 0
Q9. Consider a parallel RLC circuit having inductance of 10 mH, capacitance of 100 μF.
Determine the value of resistance that would lead to a critically damped response?
(a) 5 Ω
(b) 10 Ω
(c) 20 Ω
(d) 15 Ω
Q10. In a dynamometer type wattmeter, the pressure coil connected across the load terminal is
(a) Highly inductive
(b) Highly capacitive
(c) Highly resistive
(d) Non inductive
SOLUTIONS
S1. Ans.(d)
Sol. I_total=P/V=(25×1000)/200=125 A
For WAVE wound: number of parallel paths=2
∴ the current in each parallel path=I_total/2=125/2=62.5 A
S2. Ans.(b)
Sol. Air gap power or rotor input power (P_g )=stator input power-stator loss
∴P_g=50000-800=49200 W
Rotor copper loss (P_cu )=sP_g=0.005×49200=246 W
S9. Ans.(a)
Sol. For parallel RLC: ξ=1/2R √(L/C)
For critically damped: 𝜉=1
∴1=1/2R √((10×10^(-3))/(100×10^(-6) ))
⇒R=10/2 =5Ω
S10. Ans.(c)
Sol. In a dynamometer type wattmeter, the pressure coil connected across the load terminal is highly Resistive.
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