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# Quiz: Civil Engineering 9 June 2021

Quiz: Civil Engineering
Exam: HPPSC-AE
Topic: Miscellaneous

Each question carries 1 mark
Negative marking: 1/4 mark
Time: 10 Minutes

Q1. A summit curve is formed at the intersection of a 3% upgrade and a 5% downgrade what is the length of the summit curve in order to provide a stopping distance of 130 m.
(a) 271 m
(b) 298 m
(c) 307 m
(d) 340 m

Q2. Addition of sugar in concrete result in………
(a) Increase in setting time by about 1 hr.
(b) Increase in setting time by about 4 hr.
(c) Decrease in setting time by about 1 hr.
(d) Decrease in setting time by about 4 hr.

Q3. A column pinned at both the ends has length L and flexural rigidity EI can carry a critical load of:
(a) (4π^2 EI)/L^2
(b) (2π^2 EI)/L^2
(c) (π^2 EI)/L^2
(d) (π^2 EI)/〖4L〗^2

Q4. What is the percentage added for contingencies to allow for petty contingent, changes in design and changes in rates?
(a) 5% to 6%
(b) 6% to 8%
(c) 2% to 8%
(d) 3% to 5%

Q5. For a circular sewer running partially full, the proportionate wetted partially full, the proportionate wetted perimeter is given by:
(a) p/P=D/4
(b) p/P=α/(360°)
(c) p/P=α/πD
(d) p/P=α/(180°)

Q6. In plate girders vertical stiffeners are required when the ratio of clear depth of web (d) to web thickness (t)
(a) d/t>25
(b) d/t>75
(c) d/t>85
(d) d/t>95

Q7. Calculate the value of modulus of rigidity (N/mm²) if the Poisson’s ratio is 0.25 and modulus of elasticity for the material is 200 N/mm²
(a) 50
(b) 80
(c) 100
(d) 150

Q8. If the distance between two-point A and B is 1 km, the combined correction for curvature and refraction will be
(a) 0.6730 m
(b) 0.06735
(c) 1.0673
(d) 1.6730

Q9. The development length in compression for a 20 mm diameter deformed bar of grade Fe 415 embedded in concrete of grade M 25 whose design bond stress is 1.40 N/mm², is
(a) 1489 mm
(b) 1289 mm
(c) 806 mm
(d) 645 mm

Q10. If the porosity of a soil sample is 40%, void ratio for this sample is
(a) 0.50
(b) 0.70
(c) 0.60
(d) None of these

Solutions

S1. Ans.(c)
Sol. Deviation angle = N = 3 + 5= 8% = 0.08
Assuming L > S
L = (NS^2)/4.4=(0.08×(130)^2)/4.4
= 307.2 m ≃ 307 m

S2. Ans.(b)
Sol. Sugar is used as retarder in concrete. It increases in setting time by about 4 hr.

S3. Ans.(c)
Sol.

L_eff= L
P_CR=π²EI/L²

S4. Ans.(d)
Sol. 3 to 5% of total cost is added in the form of contingencies to allow for petty contingent, changes in design and changes in rates.

S5. Ans.(b)
Sol. For a circular sewer running partially full, the proportionate wetted perimeter is given by –
▭(p/P=α/(360°))
p = proportionate welted perimeter
P= wetted perimeter
α= central angle

S6. Ans.(c)
Sol. In plate girders, vertical stiffeners are required when the ratio of clear depth of web (d) to web thickness is greater than 85. its normal distance kept between 0.33 d to 1.5d.
▭(d/t>85 )

S7. Ans.(b)
Sol. Given; E = 200 N/mm², G = ?
μ = 0.25
we know that,
E=2G(1+μ)
200=2G(1+0.25)
100=G(1.25)
G=80 N\/mm^2

S8. Ans.(b)
Sol. Combined correction due to curvature & Refraction (Cc) = 0.0673 d^2
=0.0673×1^2
=0.0673 m.

S9. Ans.(d)
Sol. According to IS 456 : 2000
The development length (L_d ) = (ϕσ_st)/(4τ_bd )
→ For deformed bars τ_bd shall be increases by 60%.
→ for bars in compression τ_bd increased by 25%
L_d=(20×0.87×415)/(4×1.4×1.6×1.25)
▭(L_d= 645 mm)

S10. Ans.(d)
Sol. Given, Porosity (n) = 40% = 0.4
Void ratio (e) = ?
e=n/(1-n)=0.4/(1-0.4)=0.4/0.6=0.67

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