Quiz: Civil Engineering
Exam: THDC-Junior Engineer Trainee
Each question carries 1 mark
Negative marking: 1/4 mark
Time: 10 Minutes
Q1. A series of step without any landing in their direction is called
Q2. At a sewage treatment plant for a flow of 3 m³/sec, the cross-sectional area of grit chamber will be about
(a) 20 m²
(b) 25 m²
(c) 30 m²
(d) 10 m²
Q3. The irrigation works constructed for regulating the supply of irrigation water is called as
(d) Canal outlet and modulus
Q4. The ratio between adopted centrifugal ratios for roads and railways is
(a) 3 : 1
(b) 2 : 1
(c) 5 : 1
(d) 4 : 1
Q5. The rise or fall of head ‘h’ in a capillary tube of diameter ‘d’ and liquid surface tension σ and specific weight w is equal to
Q6. Calculate the curvature correction (in m.) if distance between the instrument and staff is 1000 m.
Q7. If the coefficient of active earth pressure is 1/3 then what is the value of coefficient of passive earth pressure?
Q8. What is the power (in kW) transmitted by a rotating shaft? (Where : P = power, N= Speed in rpm and T = Torque transmitted)
Q9. In a slab, the minimum reinforcement using steel of grade Fe 415 is –
(a) 0.12% of is gross sectional area
(b) 0.20% of is gross sectional area
(c) 0.15% of is gross sectional area
(d) 0.10% of is gross sectional area
Q10. If L_f is load factor S is shape factor and F is factor of safety in elastic design, the following:
Sol. Flight → A series of steps without any landing, platform or break in their direction.
Riser → It is the vertical distance between two successive tread.
Nosing → It is the outer projection of a tread.
Tread → It is the upper horizontal surface of a step upon which the feet is place while ascending or descending.
Sol. The horizontal velocity in grit chambers is about 0.3 m/sec.
Cross-sectional area required = Discharge/(Velocity (horizontal))
= 10 m^2.
Sol. The irrigation works constructed for regulating the supply of irrigation water is called as Regulators. The main purpose of the regulators is to regulate the discharge depth or velocity in canal.
→ Maximum value of centrifugal ratio for roads = 1/4
→ Maximum value of centrifugal ratio for railways = 1/8
So, ratio between these two = (1/4)/(1/8)
= (2 : 1)
Sol. Capillary rise or fall
h = 4σcosθ/ρgd
But ω (Weight density) = ρg,
and cos θ for water and glass = 1
Distance between the instrument and staff (d)= 1000 m. = 1 km
Correction due to curvature is given by
C_c = –0.0785 d²
C_c = –0.0785 (1)²
Sol. Power (P) = 2πNT/60 (watts)
P= 2πNT/60×1/10³ (Kilo watt)
Sol. Minimum reinforcement.
For mild steel bar → 0.15% of gross area
For HYSD bar → 0.12% of gross area
Sol. Load factor = Shape factor × factor of safety
▭(Shape factor (S)=Z_P/Z_e )
Where Z_P = plastic section modulus
Z_e = Elastic section modulus