Quiz: Civil Engineering
Exam: Punjab PSC
Topic: MISCELLANEOUS
Each question carries 1 mark
Negative marking: No negative marking
Time: 10 Minutes
Q1. Pick up the correct statement from the following
(a) The bulk density of fine aggregate is usually about 10 percent more than that of coarse aggregate of similar composition
(b) The specific gravity of aggregate is important for the determination of the moisture content
(c) The absorption and porosity of an aggregate influence the property of the concrete
(d) All options are correct
Q2. If the value of uniformity coefficient of a soil sample is nearly equal to one. This sample will be designated as:
(a) Well graded soil
(b) Uniformly graded soil
(c) Poorly graded soil
(d) None of the above
Q3. What is the psychological widening of a pavement on horizontal curve of radius 230 m for ruling speed 80 kmph?
(a) 0.455m
(b) 0.555m
(c) 0.186 m
(d) 0.136 m
Q4. 10 divisions of verniers scale are equal to 11 division of a main scale of each 0.1 mm. what is the least count of the verniers scale?
(a) 0.009
(b) 0.01
(c) 0.1
(d) 1.1
Q5. A lacing column is designed to carry 500 KN axial load. the total transverse shear resisted by lacing will be:
(a) 25 KN
(b) 6.25 KN
(c) 12.5 KN
(d) 15 KN
Q6. What do we need to do while designing an air entrained concrete?
(a) Water cement ratio is to be reduced
(b) Proportion of aggregates is to be reduced
(c) An allowance for the entrained air is made
(d) All options are correct
Q7. If the depth is 8.64 cm on a field over a base period of 10 day, then the duty is
(a) 10 hectares per cumecs
(b) 100 hectares per cumecs
(c) 864 hectares per cumecs
(d) 1000 hectares per cumecs
Q8. Bending moment M and torque T is applied on a solid circular shaft. if the maximum bending stress equals to maximum shear stress developed, the M is equals to
(a) T/2
(b) T
(c) 2T
(d) 4T
Q9. In a horizontal rectangular channel, the conjugate depths of flow before and after the hydraulic jump are observed as 0.25 m and 1.25 m, the energy loss due to jump will be:-
(a) 0.80 m
(b) 1.00 m
(c) 1.25 m
(d) 1.50 m
Q10. As per IS code, the minimum grade of concrete for the design of prestressed concrete structure is:
(a) M20
(b) M25
(c) M15
(d) M30
SOLUTIONS
S1. Ans.(d)
Sol. All options are correct.
The bulk density of fine aggregate is usually about 10 percent more than that of coarse aggregate of similar composition.
The specific gravity of aggregate is important for the determination of the moisture content.
The absorption and porosity of an aggregate influence the property of the concrete.
S2. Ans.(b)
Sol. Uniformity coefficient (C_u) = D_60/D_10
If C_u≃1→ Uniformly graded soil
C_u>6→ Well graded sand
C_u>4→ Well graded gravel
S3. Ans.(b)
Sol. Given,
R = 230 m
V = 80 kmph
W_psy= ?
W_psy=V/(9.5√R)=80/(9.5√230)=0.555m
S4. Ans. (b)
Sol. Least count = (Smallest division of one main scale)/(no.of division on vernier scale ) = 0.1/10 = 0.01
S5. Ans. (c)
Sol. Transverse shear force (V) = 2.5% of Column load = 2.5/100×500 = 12.5 KN.
S6. Ans. (d)
Sol. While designing an air entrained concrete-
Water cement ratio is to be reduced.
Proportion of aggregates is to be reduced.
An allowance for the entrained air is made.
S7. Ans. (d)
Sol. Given, ∆ =8.64 cm = 0.0864 m, B = 10 days
Duty (D) = (8.64 × B)/(∆ ) = (8.64 × 10)/(0.0864 ) = 1000 hectares per cumecs.
S8. Ans. (a)
Sol. Maximum Bending Stress (σ_max)=32M/(πD^3 )
Maximum Shear Stress (τ_max)=16T/(πD^3 )
σ_max= τ_max (as per question)
32M/(πD^3 )= 16T/(πD^3 )
M = T/2
S9. Ans.(a)
Sol. Given,y_2=1.25 m. & y_1=0.25 m.
The loss of energy ∆E is given by –
∆E=(y_2-y_1 )^3/(4y_1 y_2 )=(1.25-0.25)^3/(4×1.25×0.25) = 0.80 m.
S10. Ans.(d)
Sol. As per IS 456:2000, The Minimum M30 grade of concrete is used in post tensioned member and M40 grade of concrete is used in pre tensioned member.
