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PSPCL-JE’21 EE: Daily Practices Quiz 28-Oct-2021


Punjab State Power Corporation Ltd. (PSPCL), a power generating and distributing company of the Government of Punjab state, has released the notification for recruitment to the post of Clerk, Revenue Accountant, Junior Engineer (Electrical), Assistant Lineman & Assistant Sub Station Attendant Posts.
A total of 75 vacancies have been announced for the recruitment process of JE ELECTRICAL Engineering.

Exam Dates: 10 N0V-21 to 17 Nov-21

PSPCL-JE’21 EE: Daily Quiz

PSPCL-JE’21 EE: Daily Practices Quiz 28-Oct-2021

Each question carries 1 mark.
Negative marking: 1/4 mark
Total Questions: 06
Time: 06 min.

Q1. A SCHOTTKY diode is a:
(a) Minority carrier device
(b) Majority carrier device
(c) Both minority and majority carrier diode
(d) Fast recovery diode

Q2. Find the number of strands of ACSR conductor for 4-layer transmission line?
(a) 3
(b) 19
(c) 37
(d) 61

Q3. 100% string efficiency means
(a) self-capacitance is zero
(b) shunt capacitance is maximum
(c) self-capacitance is maximum
(d) shunt capacitance is zero

Q4. Wave-wound generators provide
(a) less current but more voltage
(b) more current but less voltage
(c) more current and more voltage
(d) none of the above

Q5. An accurate ammeter must have a resistance of:
(a) Very high value
(b) High value
(c) Low value
(d) Very low value

Q6. What is the inductive reactance if the Q of a coil is 60, and the winding resistance is 5 Ω?
(a) 12 Ω
(b) 300 Ω
(c) 30 Ω
(d) 0.083 Ω


S1. Ans.(b)
Sol. A SCHOTTKY diode is a majority carrier device and formed by the junction of a semiconductor with a metal.

S2. Ans.(c)
Sol. Number of strands for ‘n’ layers=3n^2-3n+1=3×4^2-(4×3)+1=37.

S3. Ans.(d)
Sol. If shunt capacitance is zero the charging current through each disc will be the same. This means that voltage across each disc is the same. This in turn means 100% string efficiency.

S4. Ans.(a)
Sol. Wave – wound has only two parallel paths. Wave-wound generators provide less current but more voltage.

S5. Ans.(d)
Sol. An ammeter is kept in series with the electrical circuit so that it can measure the full current of the circuit. Hence, a very low resistance is used in an accurate ammeter.

S6. Ans.(b)
Sol. Q=X_L/R=X_L/5=60
∴Inductive reactance=X_L=60×5=300 Ω

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