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NHPC-JE’21 CE: Daily Practices Quiz. 13-Sep-2021

Quiz: Civil Engineering
Exam: NHPC-JE
Topic: Miscellaneous

Each question carries 1 mark
Negative marking: 1/4 mark
Time: 8 Minutes

Q1. In order to draw parallel lines, concentric circles and parallel curves, command used in AutoCAD is:
(a) Array
(b) Parallel
(c) Copy
(d) Offset

Q2. …….. Scaffold consists of a ladder or tripod carrying a working platform on its top.
(a) Trestle
(b) Single
(c) Steel
(d) Suspended

Q3. Side face reinforcement is provided in a beam when the depth of web exceeds
(a) 300 mm
(b) 450 mm
(c) 500 mm
(d) 750 mm

Q4. If the jam density on a road designed for a free mean speed is 75 km/h is 100 vehicles/km, then the capacity flow will be:
(a) 1500
(b) 1875
(c) 2250
(d) 2760

Q5. If the degree of saturation of a partially saturated soil is 60% then air content of the soil is
(a) 40%
(b) 60%
(c) 80%
(d) 100%

Q6. Modulus of rigidity is defined as the ratio of ________.
(a) longitudinal stress and longitudinal strain
(b) volumetric stress and volumetric strain
(c) lateral stress and lateral strain
(d) shear stress and shear strain

Solutions

S1. Ans.(d)
Sol. Offset command is used in AUTO CAD in order to draw parallel lines, concentric circles and parallel curve. While array command is used to repeat the draw pattern and objects in Auto CAD.

S2. Ans.(a)
Sol. Trestle scaffold consist a leader or tripod carrying a working platform on its top. It is used for painting and repair works inside the room up to a height of 15 meters.

S3. Ans.(d)
Sol.
→ When depth of the beam exceeded 450 mm and torsion is also applied then side face reinforcement provided
→ When depth of the beam exceeded 750 mm then side face reinforcing provided.
→ Total area of side face reinforcement equal to 0.1% of gross area.

S4. Ans.(b)
Sol. Give, jam density (kj) = 75 km/h.
free mean speed (V_SF ) = 100 vehicles/km.
Maximum capacity flow (q_max) = ?
q_(max )= (V_sf×kj)/(4 )
= (75×100)/4
= 1875 veh/hr.

S5. Ans.(a)
Sol. degree of saturation (S) = 60%
Air content (a_c ) = ?
S+a_c=1
0.6 + a_c = 1
▭(a_c=0.40 )

S6. Ans.(d)
Sol. Modules of rigidity is defined as the ratio of shear stress and shear strain.
As per Hook’s law
Shear Stress ∝ shear strain
Shear stress = G × Shear strain
G = (Shear Stress)/(Shear Strain)
Where G – modules of rigidity.

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