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GATE’22 EE: Daily Practices Quiz 06-Sep-2021
Each question carries 2 marks
Negative marking: 2/3 mark
Total Questions: 05
Total marks: 10
Q1. The circuit shown in the figure is in steady state, when the switch is closed at t = 0. Assuming that the inductance is ideal, the current through the inductor at t = 0^+ equals—
(b) 0·5 A
Q2. In the figure given, for the initial capacitor voltage is zero. The switch is closed at t = 0. The final steady-state voltage across the capacitor is—
Q3. Resistance of an ammeter having range 0–5A is 1.8 Ω. It is shunted by a resistor of
0.2 Ω. What is the effective current when the pointer reads 3 A?
(a) 10 A
(b) 30 A
(c) 15 A
(d) 20 A
Q4. Two infinite parallel conductors carry current of 20 A each. The magnitude of the force between the conductor per meter length if the distance between them is 20 cm is……
(a) 2×10^(-4) N
(b) 3×10^(-4) N
(c) 4×10^(-4) N
(d) 5×10^(-4) N
Q5. Transfer function of a second order system G(s) = 100/((S^2+20S+100)) and this system is classified as-
(c) critically damped
(d) under damped
Sol. At steady state i_L (0^– )=10/10=1 A
∴i_L (0^–) = i_L (0^+) = 1 Amp
Sol. Capacitor will fully charge act an open.
∴I =20/(10+10)=1 A
ACQ: V_C (0^–) = 0
∴V_C (∞) = Voltage across 10Ω terminal⇒ V_C (∞) = 10 × 1= 10V.
Sol. Multiplying power of shunt, m=R_m/R_sh +1=1.8/0.2+1=10
Therefore, the range of ammeter increases 10 times. When the ammeter indicates 3 A, the circuit current = 3 ×10 = 30 A.
Sol. Force per unit length of two long current carrying parallel conductors is given by
F/l=(µ_0 I_1 I_2)/2πr=(4π×10^(-7)×20×20)/(2π×20×10^(-2) )=4×10^(-4) N
Sol. S²+2ξw_n S+W_n^2=0
ξ=20/(2×10)=1 → critically damped