Engineering Jobs   »   GATE 2022, GATE ELECTRICAL QUIZ,

GATE’22 EE: Daily Practices Quiz 01-Sep-2021

GATE 2022: 

GATE 2022 is being organized by IIT, Kharagpur. Through this exam, the qualified candidates get admission into master’s & direct doctoral programs in the field of Engineering/ Architecture/ Technology/ Arts & Science, etc. Qualification in GATE is mandatory for seeking admission to various institutions.

GATE’22 EE: Daily Practices Quiz 01-Sep-2021

Each question carries 2 marks
Negative marking: 0.66 mark

Total Questions: 05
Total marks: 10
Time: 12 min.

Q1. The unity feedback system shown in figure has:

GATE 2022, GATE ELECTRICAL QUIZ, |_30.1

(a) Zero steady state position error
(b) Zero steady state velocity error
(c) Steady state position error K/10units
(d) Steady state velocity error K/10 units

Q2. The block diagram shown in figure gives unity feedback closed loop control system. The steady state error in the response of the above system to unit step input is

GATE 2022, GATE ELECTRICAL QUIZ, |_40.1

(a) 25%
(b) 0.75%
(c) 6%
(d) 33%

Q3. The self GMD of a conductor with three strands each of radius ‘r and touching each other is
(a) r(0.7788×2×2)^(1\/3)
(b) r(0.7788×2×2×2)
(c) r(0.7788×2×2×2)^3
(d) r(0.7788×2×2)^3

Q4. For a medium length transmission line, A is
(a) equal to B
(b) equal to C
(c) equal to D
(d) not equal to any of the above

Q5. A 6-pole dc armature has simplex lap-connected 720 conductors, 3 turns per coil and 4 coil-sides per slot. Determine the number of slots in the armature and state whether equalizers can be employed or not.
(a) 30 slots and possible
(b) 30 slots and not possible
(c) 60 slots and possible
(d) 60 slots and not possible

SOLUTIONS

GATE 2022, GATE ELECTRICAL QUIZ, |_50.1

GATE 2022, GATE ELECTRICAL QUIZ, |_60.1

S4. Ans.(c)
Sol. A medium transmission line (π or T model) is symmetrical. Therefore, A = D.

S5. Ans.(c)
Sol. Each coil has 2 coil side.
∴total turn in per slot=4/2 ×3=6
Each turn has 2 conductors.
∴number of conductors/slots=12
∴total no. of conductors=no. of slots× no. of conductors per slot
⇒720=no.of slot×12
∴ no. of slots=720/12=60
Equalizer ring is used for lap connection.

Sharing is caring!

Thank You, Your details have been submitted we will get back to you.

Leave a comment

Your email address will not be published.