DFCCIL'21 CE: Daily Practice Quiz. 21-Aug-2021 |_00.1
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DFCCIL’21 CE: Daily Practice Quiz. 21-Aug-2021

Quiz: Civil Engineering
Exam: DFCCIL
Topic: Miscellaneous

Each question carries 1 mark
Negative marking: 1/4 mark
Time: 8 Minutes

Q1. A clay layer of thickness 10 cm and initial void ratio 0.5 undergoes settlement that final void ratio is 0.2, the settlement of the layer in cm is:
(a) 1
(b) 1.5
(c) 2
(d) 2.5

Q2. The type of rain-gauge commonly used in India for measuring rainfall is given by:
(a) weighing bucket type rain-gauge
(b) tipping bucket type rain-gauge
(c) floating type rain-gauge
(d) Simon’s rain-gauge

Q3. A water treatment plant treats 6000 m³ of water per day. If it consumes 20 kg chlorine per day, then the chlorine dosage would be
(a) 3.00 mg/l
(b) 3.75 mg/l
(c) 4.25 mg/l
(d) 3.33 mg/l

Q4. For points and crossings, maximum size of ballast is
(a) 50 mm
(b) 40 mm
(c) 25 mm
(d) none of these

Q5. In which classification the Semi-hydraulic lime falls?
(a) Class A
(b) Class B
(c) Class C
(d) Class D

Q6. Match List-I with List-II and select the correct answer using the given below the lists.

List-I                             List-II

  1. Talus                        a. Soil transported by wind
  2. Till                           b. Soil transported by gravity
  3. Loess                       c. Soil transported by glaciers
  4. Lacustrine                d. Soil deposited in lake bed deposit

(a) A-a, B-c, C-b, D-d
(b) A-b, B-c, C-a, D-d
(c) A-a, B-b, C-d, D-c
(d) A-c, B-b, C-d, D-a

Solutions

S1. Ans.(c)
Sol. H=10 cm
e_1=0.5
e_2=0.2
∆ H=?
∆H/H=∆e/(1+e)
∆H/10=((0.5-0.2))/(1+0.5)
▭(∆H=2 cm)

S2. Ans.(d)
Sol.
– Simon rain gauge is a non-recording type of rain gauge and commonly used in India.
– Natural syphon rain gauge is adopted in India. It similar to weighing bucket rain gauge. It is recording type of rain gauge.
– Tipping bucket type of rain gauge is used for measuring rain in remote areas. It is recording type of rain gauge means produce continuous plot of rainfall against time.

S3. Ans.(d)
Sol. Quantity of water treated per day = 6000 m³
Quantity of chlorine consumed per day = 20 kg.
Chlorine dosage = (Consumed chlorine per day)/(Quantity of water treated per day)
= (20×10^6 mg.)/(6000× 10^3 l.)
= 3.33 mg/l.

S4. Ans.(c)
Sol.

Type of Sleepers Size of ballast
Wooden & cost Iron sleepers

CST-9 & Through sleepers

Points & Crossing

50 mm

40 mm

25 mm

S5. Ans.(b)
Sol. Class A → Eminently hydraulic lime
Class B → Semi-hydraulic lime
Class C → Fat lime
Class D → Dolomite lime

S6. Ans.(b)
Sol. Talus → Soil transported by gravity
Till→ Soil transported by glaciers
Loess→ Soil transported by wind
Lacustrine→ Soil deposit in lake bed.

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