Quiz: Civil Engineering
Exam: DFCCIL-JE
Topic: MISCELLANEOUS
Each question carries 1 mark
Negative marking: 1/4 mark
Time: 8 Minutes
Q1. If the value of uniformity coefficient of a soil sample is nearly equal to one. This sample will be designated as:
(a) Well graded soil
(b) Uniformly graded soil
(c) Poorly graded soil
(d) None of the above
Q2. If a soil sample is dried beyond its shrinkage limit, this sample will show:
(a) No volume changes
(b) Moderate volume change
(c) Low volume change
(d) Large volume change
Q3. A soil sample has bulk density of 21 kN/m^3 and water content 8%. Dry density of the sample is:
(a) 19.00 kN/m^3
(b) 18.44 kN/m^3
(c) 22.68 kN/m^3
(d) 19.44 kN/m^3
Q4. What is the psychological widening of a pavement on horizontal curve of radius 230 m for ruling speed 80 kmph?
(a) 0.455m
(b) 0.555m
(c) 0.186 m
(d) 0.136 m
Q5. 10 divisions of verniers scale are equal to 11 division of a main scale of each 0.1 mm. what is the least count of the verniers scale?
(a) 0.009
(b) 0.01
(c) 0.1
(d) 1.1
Q6. A dry soil has mass specific gravity of 1.35. If the specific gravity of solids is 2.7 then the void ratio will be
(a) 0.5
(b) 1.0
(c) 1.5
(d) 2.0
SOLUTION
S1. Ans.(b)
Sol. Uniformity coefficient (C_u) = D_60/D_10
If C_u≃1→ Uniformly graded soil
C_u>6→ Well graded sand
C_u>4→ Well graded gravel
S2. Ans.(a)
Sol. The shrinkage limit is the water content where further loss of moisture will not result in any volume reduction.
S3. Ans.(d)
Sol. Given,
γ_b=21 kN/m^3
w=8%=0.08
γ_d=?
γ_d=γ_b/(1+w)=21/(1+0.08)=19.44 kN/m^3
S4. Ans.(b)
Sol. Given,
R = 230 m
V = 80 kmph
W_psy= ?
W_psy=V/(9.5√R)=80/(9.5√230)=0.555m
S5. Ans. (b)
Sol. Least count = (Smallest division of one main scale)/(no.of division on vernier scale ) = 0.1/10 = 0.01
S6. Ans. (b)
Sol. Given,
G_m=1.35
G_s=2.7
e= ?
G_m=G_s/(1+e)
1.35=2.7/(1+e)
â–(e= 1.0)
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