DFCCIL (Dedicated Freight Corridor Corporation of India Limited) Exam Date 2021 on September and October 2021 so boost your preparation by attempt this Civil Engineering MISCELLANEOUS quiz for DFCCIL recruitment 2021.
Quiz: Civil Engineering
Exam: DFCCIL-JE
Topic: MISCELLANEOUS
Each question carries 1 mark
Negative marking: 1/4 mark
Time: 12 Minutes
Q1.A set period of time break of construction project has completed during which a contractor has the right to return to the site to remedy defects is known as
(a) Contractor maintenance period
(b) Maximum construction period
(c) Maximum defect period
(d) Defect liability period
Q2.The expected out turn of 2.5 cm cement concrete floor per mason per day
(a) 2.5 sqm
(b) 5.0 sqm
(c) 7.5 sqm
(d) 10 sqm
Q3. Hollow bricks are generally used with the purpose of ______.
(a) Reducing the cost of construction
(b) Providing insulation against heat
(c) Increasing the bearing area
(d) Ornamental look
Q4. The ratio of maximum and average shear stresses on a rectangular section is _____.
(a) 1
(b) 1.25
(c) 1.5
(d) 2
Q5. The increased cohesiveness of concrete, makes it __________.
(a) Less liable to segregation
(b) More liable to segregation
(c) More liable to bleeding
(d) More liable for surface scaling in frosty weather
Q6. At yield point of a test piece, the material _____.
(a) Obeys Hooke’s law
(b) Behaves in an elastic manner
(c) Regains its original shape on removal of the load
(d) Undergoes plastic deformation
SOLUTION
S1. Ans.(d)
Sol. A set period of time break of construction project has completed during which a contractor has the right to return to the site to remedy defects is known as defects liability period.
S2. Ans.(c)
Sol. The expected out turn of 2.5 cm cement concrete floor per mason per day is 7.5 m².
S3. Ans.(b)
Sol. The air present in the hollow area of these bricks make them thermal insulators. They keep the interiors cool in summer and warm in winter especially the ‘clay hollow bricks’. They also provide more sound insulation as compared to solid bricks.
S4. Ans.(c)
Sol. ● The ratio of maximum shear stress to average shear stress is 4/3 or 1.33 in circular cross-section.
● The ratio of maximum shear stress to average shear stress is 3/2 or 1.5 in rectangular cross-section.
● The ratio of maximum shear stress to average shear stress is 3/2 or 1,5 in triangular cross-section.
S5. Ans.(a)
Sol. When the cohesive property of concrete increases, then there will be more chance of generation bonding between each particle in concrete, so there will be no chance of segregation (Separation of particles) or we can say that it makes less liable to segregation.
S6. Ans.(d).
Sol. At yield point of a test piece, the material undergoes plastic deformation. When material obeys hooks law, it is the limit of proportionality and when material regains its original shape on removal of the load, it is its elastic limit.
