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# DFCCIL’21 CE: Daily Practice Quiz. 04-Aug-2021

Quiz: Civil Engineering
Exam: DFCCIL-JE
Topic: MISCELLANEOUS

Each question carries 1 mark
Negative marking: 1/4 mark
Time: 8 Minutes

Q1. A vehicle is travelling at 80 km per hour. Assuming that the driver’s perception time is 1.5 second and the reaction time is 0.5 second, what is the stopping distance on a dry level concrete pavement for which the coefficient of friction between the pavement and the tyre is 0.35?
(a) 116.4 m
(b) 117.4 m
(c) 115.4 m
(d) 116.0 m

Q2. If the stopping distance and average length of a vehicle are 18 m and 6 m respectively, then the theoretical maximum capacity (vehicles per hour) of a traffic lane at a speed of 10 m/sec is
(a) 1500
(b) 2000
(c) 2500
(d) 3000

Q3. Bottom-most component of a flexible pavement, is
(b) Sub-base
(c) Surface course
(d) Base course

Q4. The width of formation for a two-lane road for national highway is
(a) 10.0 m
(b) 12.0 m
(c) 14.0 m
(d) 16.0 m

Q5. Peak hour factor is expressed in percentage of
(c) PCU
(d) DF

Q6. A rail is designated by its
(a) Length
(b) Weight per unit length
(c) Only weight
(d) Cross-section

SOLUTION

S1. Ans.(a)
Sol. Given, Velocity (V) = 80 kmph
Total reaction time(t) = Perception time + Reaction time
= 1.5 + 0.5
T = 2 seconds
Coefficient of friction (f) = 0.35
Now,
Stopping sight distance (SSD) = vt+v^2/2gf
=80/3.6×6+(80/3.6)^2/(2×9.8×0.35)
=44.44+71.986
=116.430 m.

S2. Ans.(a)
Sol. Given,
Space headway (S) = sight distance + average length of vehicle (L)= 18 + 6 = 24 m.
Speed (V) = 10 m/sec = 10 × 3.6 = 36 km/hour
Theoretical maximum capacity (C) = 1000V/S
=(1000× 36 )/24
=1500 veh.\/hour

S3. Ans.(a)
Sol. Bottom – most component of a flexible pavement is subgrade.

S5. Ans.(b)
Sol. Peak hour factor is expressed in percentage of annual average daily traffic (AADT) and it is used in the design of transportation facilities and major projects.

S6. Ans.(b)
Sol. A rail is designated by its weight per unit length.

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